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3 years ago

How do I figure out what 1/10 of 6000 is?

1 answer:

5 0

The way I like to figure out problems like this is to write it out like,

1/10 = x/6000
(One over ten equals x over 6000)

Then you find out how much you multiplied 10 by to get 6000. To do this you can divide 6000 by 10 getting 600. The rule "what you do to the bottom you have to do to top" in this equation. So since you multiplied the bottom by 600 you have to multiply the top by 600 as well. 600 times 1 is just 600.

So your answer is, 600 is 1/10 of 6000.

Hope this helps and isn't too confusing.

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Write 1 over 16 as a decimal

mihalych1998 [28]

Answer:

.0625

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

For 0 ≤ ϴ < 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va

Black_prince [1.1K]

Answer:

3 solutions:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is $tan(\frac{\theta}{2})$ so let's focus on that part of the equation first.

We know that:

$tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}$

therefore:

$cos(\frac{\theta}{2})\neq0$

so we need to find the angles that will make the cos function equal to zero. So we get:

$cos(\frac{\theta}{2})=0$

$\frac{\theta}{2}=cos^{-1}(0)$

$\frac{\theta}{2}=\frac{\pi}{2}+\pi n$

$\theta=\pi+2\pi n$

we can now start plugging values in for n:

$\theta=\pi+2\pi (0)=\pi$

if we plugged any value greater than 0, we would end up with an angle that is greater than $2\pi$ so, that's the only angle we cannot include in our answer set, so:

$\theta\neq \pi$

having said this, we can now start solving the equation:

$tan(\frac{\theta}{2})=sin(\theta)$

we can start solving this equation by using the half angle formula, such a formula tells us the following:

$tan(\frac{\theta}{2})=\frac{1-cos(\theta)}{sin(\theta)}$

so we can substitute it into our equation:

$\frac{1-cos(\theta)}{sin(\theta)}=sin(\theta)$

we can now multiply both sides of the equation by $sin(\theta)$

so we get:

$1-cos(\theta)=sin^{2}(\theta)$

we can use the pythagorean identity to rewrite $sin^{2}(\theta)$ in terms of cos:

$sin^{2}(\theta)=1-cos^{2}(\theta)$

so we get:

$1-cos(\theta)=1-cos^{2}(\theta)$

we can subtract a 1 from both sides of the equation so we end up with:

$-cos(\theta)=-cos^{2}(\theta)$

and we can now add $cos^{2}(\theta)$

to both sides of the equation so we get:

$cos^{2}(\theta)-cos(\theta)=0$

and we can solve this equation by factoring. We can factor $cos(\theta)$ to get:

$cos(\theta)(cos(\theta)-1)=0$

and we can use the zero product property to solve this, so we get two equations:

Equation 1:

$cos(\theta)=0$

$\theta=cos^{-1}(0)$

$\theta={\frac{\pi}{2}, \frac{3\pi}{2}}$

Equation 2:

$cos(\theta)-1=0$

we add a 1 to both sides of the equation so we get:

$cos(\theta)=1$

$\theta=cos^{-1}(1)$

$\theta=0$

so we end up with three answers to this equation:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

7 0

3 years ago

Your brother lends you $125 at an annual interest rate of 25%. If you want to pay no more than $62.50 in simple interest, in how

iren2701 [21]

3. You purchase a car using a $20,000 loan with a 5% simple interest rate. (a) How much interest do you pay on your loan if you pay off the loan in 4 years? Show your work. (b) How much interest do you pay on your loan if you pay off the loan in 2 years? Show your work. (c) How much interest do you save by paying the loan off in 2 years instead of 4? Show your work. Answer:

7 0

4 years ago

Hi My question is what is 12% of 21

vfiekz [6]

Answer:

2.52

Step-by-step explanation:

21*.12=

2.52

5 0

3 years ago

Can someone please help me With BOTH parts of the question ..thanks u

Gala2k [10]

Answer:

-0.89 < -0.51

B. Felipe's Restaurant has less value than Ming's Lodge.

Step-by-step explanation:

If you have a big debt you're going to have less money.

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3 years ago