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KiRa [710]
2 years ago
15

What force would have been applied to the bus from t=16 s to t=21 s? Assume the mass of the bus was 50 kg.

Mathematics
1 answer:
Svetllana [295]2 years ago
7 0

Applying Newton's Second Law, it is found that the force, in Newtons, is given by:

F = 10[v(21) - v(16)]

Newton's Second Law states that Force, in Newtons, is <u>mass times acceleration</u>, that is:

F = ma

In this problem, mass of 50 kg, thus m = 50

Acceleration is <u>change in velocity divided by change in time</u>, that is:

a = \frac{\Delta_v}{\Delta_t}

In this problem, we don't know the velocities, but know that time is from 16s to 21s, thus:

\Delta_t = 21 - 16 = 5

\Delta_v = v(21) - v(16)

Thus, the force is given by:

F = ma

F = m\frac{\Delta_v}{\Delta_t}

F = 50\frac{[v(21) - v(16)]}{5}

F = 10[v(21) - v(16)]

A similar problem is given at brainly.com/question/18801986

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Arjun can type 40 words per minute.Dalia can type 55 words per minute.If Arjun and Dalia each type for 30 minutes,about how many
Citrus2011 [14]
♥ Solve:
(Arjun) 40*30=1200
(Dalia) 55*30=1650
Now subtract
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8 0
3 years ago
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A tent forms an equilateral triangular prism, with both triangular faces exposed. each side of the triangular face has a length
Soloha48 [4]
Given:
Equilateral Triangular Prism
Each side of the triangular face has a length of 196cm
The tent is 250cm long

I have attached an image of the tent. Since the height of the tent is also the height of the triangle, I will solve for the height of the triangle using Pythagorean theorem.

I divided the equilateral triangle into 2 right triangle. The height then becomes the long leg of the triangle. The hypotenuse is 196cm and the short leg is 98cm, half of one side of the triangle.

a² + b² = c²
a² = c² - b²
a² = (196cm)² - (98cm)²
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The height of the tent is 169.74 centimeters. 

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