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mina [271]
2 years ago
13

Please help! I need this ASAP

Mathematics
1 answer:
8_murik_8 [283]2 years ago
4 0

Answer:

  (c)  22

Step-by-step explanation:

The range of a set of data is found from a box and whisker plot by subtracting the lower whisker value from the upper whisker value:

  range = 66 -44 = 22

The range in the number of pretzels is 22.

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Can someone please tell me the answer on this.
marishachu [46]

Answer: x = 31

Step-By-Step:

<u>To Find x:</u>

<u />\left(2x+20\right)+\left(x+10\right)+\left(2x-5\right)=180 (Angle Sum Property Of Triangles)

(Remove the brackets)

<u />2x+20+x+10+2x-5=18<u />

(Group Accordingly)

<u />2x+x+2x+20+10-5=180<u />

= 5x+20+10-5=180

= 5x\:+\:25 =180

= 5x= 180 - 25

= 5x = 155

= x=\frac{155}{5}

= 31

<u>Therefore</u> x = 31

So,

Angle A = x + 10 = 31 + 10 = 41

Angle B = 2*x + 20 = 2*31 + 20 = 82

Angle C = 2*x - 5 = 62 - 5 = 57

5 0
2 years ago
A rectangle has a height of 777 and a width of 2x^2-32x
Murljashka [212]
<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write clear questions in order to get good and exact answers. Here I'll assume the data given in a comment above. So:

H:height \\ \\ W:Width \\ \\ \\ H=7 \\ \\ W= 2x^2-32x+2

We know that the area (A) of any rectangle is given by:

A=H\times W \\ \\ A=7(2x^2-32x+2) \\ \\ \\ Expanding: \\ \\ A=(7)(2x^2)-(7)(32x)+(7)(2) \\ \\  \boxed{A=14x^2-224x+14}

8 0
3 years ago
Name the intersection of AB and CD
Vlad1618 [11]

Answer:

two lines, AB and CD, intersect at point E. find the values of x and y given that: the measure of angle AED equals (10x+9y), the measure of angle AEC equals (xy), and the measure Algebra -> Angles -> SOLUTION: two lines, AB and CD, intersect at point E. find the values of x and y given that: the measure of angle AED equals (10x+9y), the measure of angle AEC equals (xy), and the measure Log On

Step-by-step explanation:

7 0
3 years ago
Need help to do this
sweet [91]
A graphing calculator can help you visualize the function and its various behaviors.

6. The horizontal and vertical asymptotes are y=1, x=4, and there is a "hole" at x=-2. The appropriate choice is ...
  F. Oblique asymptote y = 0

8. The denominator has degree 2 more than the numerator, so the end behavior will tend toward 0 as x gets large. The appropriate choice is ...
  J. As x → ±∞, f(x) → 0

8 0
3 years ago
160 prime factors in ascending order
igor_vitrenko [27]

I'd arbitrarily begin by writing the factors 10 and 16.  These, in turn, factor to 2 and 5.  That's all we need to do here to form the product 160, using 5 once and 2 several times:

160 = 5 * 2^5

4 0
3 years ago
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