Question

What is the factorization of 121b^4 − 49?

Answer 1

Answer:

(11b^2 + 7) (11b^2 - 7)

Explanation:

Since both terms are perfect squares, factor using the difference of squares formula,  a^2 - b^2 = (a + b) (a - b) where a = 121b^4 and b = 49