3 years ago

What is the factorization of 121b^4 − 49?

1 answer:

3 0

Answer:

(11b^2 + 7) (11b^2 - 7)

Explanation:

Since both terms are perfect squares, factor using the difference of squares formula, a^2 - b^2 = (a + b) (a - b) where a = 121b^4 and b = 49

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