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3 years ago

EASY QUESTION, BASIC, FOR 75 AMAZING POINTS!

Mathematics

2 answers:

docker41 [41]3 years ago

6 0

The point P in the triangle is called the centroid.

⇒The centroid would actually be the center of mass.

⇒The centroid of a triangle is just going to be the average of the coordinates of the vertices.

balu736 [363]3 years ago

3 0

Point P is the orthocenter of the triangle.

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A1+a2+a3=180 solve for a1

Leviafan [203]

Answer: a1=180-a2-a3....

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3 years ago

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The values of x and y are proportional. Determine the constant of proportionality(k)

Studentka2010 [4]

<h3>The constant of proportionality is k = 5</h3>

For direct proportion equations, you divide the y value over its corresponding x value to get the value of k.

For example, the point (x,y) = (2,10) is on the diagonal line. So k = y/x = 10/2 = 5.

Another example: the point (x,y) = (6, 30) is also on the same diagonal line, so k = y/x = 30/6 = 5 is the same result as before.

You can use any point on the diagonal line as long as it is not (0,0). This is because division by zero is not allowed.

side note: the direct proportion equation y = k*x becomes y = 5*x which is the graph of that diagonal line. The slope is m = 5, the y intercept is b = 0. All direct proportion graphs go through the origin as shown in the diagram.

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3 years ago

Monomials. Please help. I have a test (m^8)^5

cricket20 [7]

Answer:

$m^{40}$

Step-by-step explanation:

$(m^8)^5=m^{8*5} =m^{40}$

Hope this helps!

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2 years ago

Jenny earned a 77 on her most recent test. Jenny’s score is no less than 5 points greater than Four-fifths of Terrance’s score.

lina2011 [118]

77 5 + 4/5t

Is the answer!

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3 years ago

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For a certain candy, 20% of the pieces are yellow, 15% are red, 20% are blue, 20% are green, and the rest are brown. a

OLEGan [10]

Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

Brown: $\frac{25}{100}$
Yellow or Blue: $\frac{20}{100} +\frac{20}{100} = \frac{40}{100}$ ....add the numerators

Not Green: $\frac{80}{100}$ .... since the sum of all the rest is 80%

Stiped: $\frac{25}{100}$ .... there are 0 striped candies.

Assuming the ratios/percentages of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.

3 Browns: $\frac{25*25*25}{100*100*100} = \frac{15,625}{1,000,000} = \frac{1.5625}{100}$

the 1st and 3rd are red while the middle is any. We multiply 15% * (total of all minus red which is 85%) * 15% like so.

$\frac{15*85*15}{100*100*100} = \frac{19,125}{1,000,000} = \frac{1.9125}{100}$

None are Yellow: multiply the percent of all minus yellow three times.

$\frac{80*80*80}{100*100*100} = \frac{512,000}{1,000,000} = \frac{51.2}{100}$

At least 1 green: multiply the percent of green by 100% twice, since the other two can by any

$\frac{20*100*100}{100*100*100} = \frac{200,000}{1,000,000} = \frac{20}{100}$

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3 years ago