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statuscvo [17]
4 years ago
15

Find the 91st term of the arithmetic sequence 28, 8, -12, ...

Mathematics
1 answer:
lesya692 [45]4 years ago
3 0

Answer:

Step-by-step explanation:

The explicit formula for an arithmetic sequence is

a_n=a_1+d(n-1)

where n is the position of the number in the sequence, a1 is the first number in the sequence, and d is the common difference between the numbers.  

If we are looking for the 91st term, our n = 91;

our a1 is 28, and

the common difference is -20.  Putting all that together gives us the explicit formula for this sequence:

a_{91}=28-20(91-1) and

a_{91}=28-20(90) and

a_{91}=28-1800 so

a_{91}=-1772

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or 3 as it has the highest probability

Step-by-step explanation:

                       X      P(X)          X .P(X)         X²     X².P(X)

                        0       0.1                 0            0           0

                         1        0.17             0.17         1           0.17

                        2       0.21             0.42         4         0.84

                        3       0.32            0.96          9         2.88

<u>                          4       0.2               0.8           16       3.2  </u>

<u>∑                     10          1                   2.35         30     7.09</u>

Let X represent an event that the student has passed with at least a 2.

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e. P(all pass) = P(A) +P(B) +P(C)= 0.2+ 0.32+ 0.21= 0.73

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