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2 years ago

Figure EFGH is transformed to E’F’G’H’, as shown:

Mathematics

1 answer:

lana [24]2 years ago

3 0

Answer:

Figure EFGH is congruent to figure E’F’G’H’.

Step-by-step explanation:

Reflection does not change size or shape. It only changes orientation. A reflected figure is congruent to the original.

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What is 25% of $8? $ Submit

vekshin1

Answer:

2 dollars?

Step-by-step explanation:

8 divided by 4

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2 years ago

What is the vertex and axis of symmetry for y=4x^2-12x+9?

VLD [36.1K]

Answer:

axis of symmetry x=3/2

vertex (3/2, 0)

Step-by-step explanation:

to find the axis of symmetry we use h = -b/2a

where ax^2 + bx+c

h = -(-12)/2(4)

h= 12/8

h = 3/2

the axis of symmetry is x = 3/2

the x coordinate of the vertex is h x=3/2

to find k, the y coordinate of the vertex, substitute x=3/2 into the equation

y=4x^2-12x+9

y=4(3/2) ^2-12(3/2)+9

= 4 (9/4) - 6*3 +9

= 9-18+9

= 0

the vertex (3/2, 0)

4 0

3 years ago

Neeeddddd helpppp ASAP!!!!!

Artist 52 [7]

The third answer is correct.

5 0

3 years ago

American cars maker produce 5650000 cars each year in Europe that Americans make 6 million 550 cars the mistake did Ben make how

Vlad [161]

Answer:

Ben has mixed up the digit for millions and hundred thousands: he wrote 5 in the place for millions and 6 in the place for hundred thousands, but it should be the other way. I think that he should exchange those two digits in the faulty report.

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2 years ago

Solve the proportion

mario62 [17]

Answer:

$\boxed{\sf x = 5}$

Step-by-step explanation:

$\sf Solve \: for \: x \: over \: the \: real \: numbers: \\ \sf \implies \frac{2}{x - 3} = \frac{5}{x} \\ \\ \sf Take \: the \: reciprocal \: of \: both \: sides: \\ \sf \implies \frac{x - 3}{2} = \frac{x}{5} \\ \\ \sf Expand \: out \: terms \: of \: the \: left \: hand \: side: \\ \\ \sf \implies \frac{x}{2} - \frac{3}{2} = \frac{x}{5} \\ \\ \sf Subtract \: \frac{x}{5} - \frac{3}{2} \: from \: both \: sides: \\ \sf \implies \frac{x}{2} - \frac{3}{2} - ( \frac{x}{5} - \frac{3}{2} ) = \frac{x}{5} - ( \frac{x}{5} - \frac{3}{2} ) \\ \\ \sf \implies \frac{x}{2} - \frac{3}{2} - \frac{x}{5} + \frac{3}{2} = \frac{x}{5} - \frac{x}{5} + \frac{3}{2} \\ \\ \sf \frac{x}{5} - \frac{x}{5} = 0 : \\ \sf \implies \frac{x}{2} - \frac{x}{5} - \frac{3}{2} + \frac{3}{2} = \frac{3}{2} \\ \\ \sf \frac{3}{2} - \frac{3}{2} = 0: \\ \sf \implies \frac{x}{2} - \frac{x}{5} = \frac{3}{2} \\ \\ \sf \frac{x}{2} - \frac{x}{5} = \frac{5x - 2x}{10} = \frac{3x}{10} : \\ \sf \implies \frac{3x}{10} = \frac{3}{2} \\ \\ \sf Multiply \: both \: sides \: by \: \frac{10}{3} : \\ \sf \implies \frac{3x}{10} \times \frac{10}{3} = \frac{3}{2 } \times \frac{10}{3} \\ \\ \sf \frac{3x}{10} \times \frac{10}{3} = \cancel{\frac{3}{10} } \times( x) \times \cancel{ \frac{10}{3} } = x : \\ \sf \implies x = \frac{3}{2} \times \frac{10}{3} \\ \\ \sf \frac{3}{2} \times \frac{10}{3} = \cancel{ \frac{3}{2} } \times \cancel{ \frac{3}{2} } \times 5 : \\ \sf \implies x = 5$

8 0

3 years ago