Question

(3x^4y^5) ^ 3/7 in radical form

Answer 1

The expression in radical form is $(\sqrt[7]{3x^4y^5}) ^3$

In order to express the given indices expression in radical form, we need to ensure there is a square root present in the resulting expression.

According to the law of indices,

$a^{m/n} = \sqrt[n]{m}$

Given the indices $(3x^4y^5) ^ {3/7}$

Comparing with the general formula, we will see that:

m = 3

n = 7

a = $3x^4y^5$

Applying the law of indices:

$(3x^4y^5) ^ {3/7} = (\sqrt[7]{3x^4y^5}) ^3$

Hence the expression in radical form is $(\sqrt[7]{3x^4y^5}) ^3$

Learn more here: brainly.com/question/6755932