We need to solve x+2y=11 for x
Let's start by adding -2y to both sides
x+2y -2y = 11-2y
x= -2y+11
Now substitute -2y+11 for x in x-2y =-1
x-2y=-1
-2y+11-2y=-1
-4y+11=-1
Add -11 to both sides
-4y+11-11=-1-11
-4y=-12
Divide both sides by -4
-4y/-4 = -12/-4
y= 3
Substitute 3 for y in x=-2y+11
x= -2y+11
x = (-2)(3)+11
x=-6+11
x=5
The answer is x=5 and y=3
(5,3)
I hope that's help:)
X(p-6) = z-8 => x = (z-8)/(p-6) if p≠6
Answer:
B) -3 (Sorry if its overwhelming)
Explanation:
First, we have the given information of the weather over a <em>2</em> and <em>1/5</em> <em>span</em>
And we are asked to find the change per hour
We can first start by finding the <em>change</em> for 2 and 1/5 hours:
- Subtract the first amount by the second amount.
= (-6 3/5) - 0
= (-6 3/5) + 0
= -6 3/5
Now that we have the change for <em>2 and 1/5 hours</em> we must find the <em>change</em> per hour:
- Divide the given dividend by the given divisor
= -6 3/5 ÷ 2 1/5
= -3
Hence, the temperature <em>change per hour</em> over a 2 1/5 hour span is -3° per hour
Answer:
y = 
x
Step-by-step explanation:
the equation of a line passing through the origin is
y = mx ( m is the slope )
calculate m using the slope formula
m = 
with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (6, 3) ← 2 points on the line
m = 
= 
=
y = x ← equation of line
Answer:
SAS
Step-by-step explanation:
We must prove that triangles ABC and EDC are congruent.
Since BD bisects AE, then AC is congruent with CE.
Since AE bisects BD, then BC is congruent with CD
Angle C is 90° in the triangle EDC and is also 90° in triangle BCA because they are vertical angles.
Being two sides and the included angle congruent, then both triangles are similar by the SAS theorem.
Answer: SAS
