Answer:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
Let X the random variable of interest for a population. We know from the problem that the distribution for the random variable X is given by:
We take a sample of n=64 . That represent the sample size.
The sample mean is defined as:
And if we find the expected value and variance for the sample mean we got:
Var(\bar X) = \frac{\sigma^2}{n}[/tex]
The distribution for the sample mean is given by:
Answer:
X= z/3 - y/3
Step-by-step explanation:
Answer:
Side GI= 2
Step-by-step explanation:
Photo attached, used SOH CAH TOA method.
Remark
The basic equation is y = mx + b
y = the total amount of money
m = The amount of money he save each month (it is a constant).
b = the y intercept which is his starting amount or 120 dollars.
x = the number of months (this is a variable).
After 3 months he has 840 dollars. That's y
840 = 3*m + 120 Subtract 120 from both sides
840 - 120 = 3m
720 = 3m
240 = m So he saves 240 every month.
Now the equation becomes.
y = 240 * x + 120
Savings after 24 months
y = Total
m = 240 dollars/month
x = 24 months
b = 120
y = 24*240 + 120
y = 5760 + 120
y = 5580
He had 5580 dollars after saving for 2 years (or 24 months total) This assumes that when he started, he took his birthday money and added a 1 month payment to it
-8w+3z
w=2.2
z=-9.1
-8(2.2)+3(-9.1)
-17.6-27.3
-44.9
The answer is -44.9
