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soldier1979 [14.2K]
3 years ago
12

2/8 and 5/8 in simplest form

Mathematics
2 answers:
zloy xaker [14]3 years ago
8 0

Answer:

2/8= 1/4 5/8 is in simplest form.

Step-by-step explanation:

8090 [49]3 years ago
4 0

Answer:

2/8 is simplest form is 1/4 and 5/8 in simplest form is just 5/8

Step-by-step explanation:

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−5.2 + y = 7.5 which one please answer...
nirvana33 [79]

Answer:

Step-by-step explanation:

y= 12.7

so -5.2 +12.7=7.5

8 0
3 years ago
Read 2 more answers
What is an Expression similar to 3/4(5z+16)
tino4ka555 [31]
Distribute the 3/4 into the parenthesis.
should get (15/4)Z+ 48/4
then simplify
Final answer= (15/4)Z+12
7 0
3 years ago
Which expression is equivalent to 36 / 4?
barxatty [35]

Answer:

9

Step-by-step explanation:

divide 36 by 4 and its nine

7 0
3 years ago
A door delivery florist wishes to estimate the proportion of people in his city that will purchase his flowers. Suppose the true
zloy xaker [14]

Answer:

The probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.009.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

As the sample size is large, i.e. <em>n</em> = 492 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by the normal distribution.

The mean and standard deviation of the sampling distribution of sample proportion are:

\mu_{\hat p}=p=0.07\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.07(1-0.07)}{492}}=0.012

Compute the probability that the sample proportion will differ from the population proportion by greater than 0.03 as follows:

P(|\hat p-p|>0.03)=P(|\frac{\hat p-p}{\sigma_{\hat p}}|>\frac{0.03}{0.012})

                           =P(|Z|>2.61)\\\\=1-P(|Z|\leq 2.61)\\\\=1-P(-2.61\leq Z\leq 2.61)\\\\=1-[P(Z\leq 2.61)-P(Z\leq -2.61)]\\\\=1-0.9955+0.0045\\\\=0.0090

Thus, the probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.009.

5 0
3 years ago
An online music store offers 2 downloads for $7.50. Another online music store offers 12 downloads for $20.20 which store offers
Dvinal [7]

Answer:

the second store has the better deal.

Step-by-step explanation:

12 ÷ 2 = 6

7.5 × 6 = 45

20.2 < 45

5 0
3 years ago
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