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labwork [276]
2 years ago
7

The rate of change of velocity is called:.

Physics
1 answer:
Pavel [41]2 years ago
6 0

Answer: Acceleration

Detailed Explanation:

Acceleration is defined as the rate of change of velocity.

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When hydrogen is heated or subjected to an electric discharge, it emits light with specific visible wavelengths. A diffraction g
BartSMP [9]

To solve this problem we will apply the concepts related to the double slit-experiment. For which we will relate the distance between the Slits and the Diffraction Angle with the order of the bright fringe and the wavelength, this is mathematically given as,

d sin\theta = m\lambda

Here,

d = Distance between Slits

m = Order of the fringes

\lambda = Wavelength

\text{Spacing between adjacent lines} = d = 4926nm

\text{Wavelength of light} = \lambda = 656nm

Rearranging to find the angle,

sin\theta = \frac{m\lambda}{d}

\theta = sin^{-1}(\frac{m\lambda}{d})

\theta = sin^{-1}(\frac{(4)(656*10^{-9}m)}{4926*10^{-9}m})

\theta = 32.19\°

Therefore the angle that the fourth order bright fringe occur for this specific wavelenth of light occur is 32.19°

3 0
3 years ago
A toy car is moving across a table with a velocity of 7.0 m/s and drives off the end. The table is 1.8 m tall. How long will the
KatRina [158]

Answer:

Option D - 0.2 s

Explanation:

We are given;

Initial velocity; u = 7 m/s

Height of table; h = 1.8m

Now,since we want to find the time the car spent in the air, we will simply use one of Newton's equation of motion.

Thus;

h = ut + ½gt²

Plugging in the relevant values, we have;

1.8 = 7t + ½(9.8)t²

4.9t² + 7t - 1.8 = 0

Using quadratic formula to find the roots of the equation gives us;

t = -1.65 or 0.22

We can't have negative t value, thus we will pick the positive one.

So, t = 0.22 s

This is approximately 0.2 s

7 0
3 years ago
Find average speed when time= 27s and total distance is 94m
Slav-nsk [51]
3.4814815 (or 3 13/27) m/s

speed = distance/time
3.4814815 (or 3 13/27) = 94/27

8 0
3 years ago
When was the copernican treatise published
LiRa [457]
They were published in 1542.

5 0
3 years ago
What is the kinetic energy of a 74.0 kg skydiver falling at a terminal velocity of 52.0m/s?
skad [1K]

Answer:

100,048

Explanation:

K.E = 1/2 m (v)^2

K.E = 1^/2 * 74 * (52)^2

K.E = 100,048J =100.048kJ

8 0
3 years ago
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