Answer:
f1 = 58.3Hz, f2 = 175Hz, f3 = 291.6Hz
Explanation:
lets assume speed of sound is 350 m/s.
frequencies of a standing wave modes of an open-close tube of length L
fm = m(v/4L)
where m is 1,3,5,7......
and fm = mf1
where f1 = fundamental frequency
so therefore: f1 = 350 x 4 / 1.5
f1 = 58.3Hz
f2 = 3 x 58.3
f2 = 175Hz
f3 = 5 x 58.3
f3 = 291.6Hz
Answer:
5.1 x 10¹⁰s
Explanation:
Given parameters:
Decay constant = 13.6 x 10⁻¹²/s
Unknown:
Half life of the element = ?
Solution:
From the decay constant, we can find the half-life of this radioactive element.
Half-life = 
Half-life = 
= 5.1 x 10¹⁰s
Answer: No
Explanation:
The number of neutrons is equal to the difference between the mass number of the atom (M) and the atomic number (Z).
Answer:
40.1m/s
Explanation:
This is a kinematics problem
x = 82m
a = -9.8m/s^2
v(initial) = 0
Find: v(final)
Using kinematics equation:
vf^2 = vi^2 + 2a(delta)x
vf^2 = 0 + 2*(-9.8)*(82)
vf = sqrt(1607.2) = 40.09m/s
The is traveling with a velocity of 40.1m/s when it hits the ground.
Answer:
2
Explanation:
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