Answer:
322 kJ
Explanation:
The work is the energy that a force produces when realizes a displacement. So, for a gas, it occurs when it expands or when it compress.
When the gas expands it realizes work, so the work is positive, when it compress, it's suffering work, so the work is negative.
For a constant pressure, the work can be calcutated by:
W = pxΔV, where W is the work, p is the pressure, and ΔV is the volume variation. To find the work in Joules, the pressure must be in Pascal (1 atm = 101325 Pa), and the volume in m³ (1 L = 0.001 m³), so:
p = 60 atm = 6.08x10⁶ Pa
ΔV = 82.0 - 29.0 = 53 L = 0.053 m³
W = 6.08x10⁶x0.053
W = 322x10³ J
W = 322 kJ
Answer:
-1
Explanation:
An atom contains a proton, electron and neutron as subatomic particles. The number of protons, which is the positively charged particle (+) is always equal to the number of electrons, which is the negatively charged particle (-) in A NEUTRALLY CHARGED ATOM i.e. no charge.
However, a decrease or increase in charge is dependent on the number of electrons and protons in that atom. Sulfur atom has an electron number of 16 in its neutral atom, however, when it gains one more electron to become 17, it means that the charge has become -1 because the charge = number of protons - number of electrons i.e. 16 - 17 = -1.
Hello!
<span>Let us apply the time function of space, in the uniform uniform motion (UUM)
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Formula:

Data:
S (Final position) = 30 m
So (Initial Position) = 0 m
Vo (Initial velocity) = 0 m/s
t (time) = ? (in seconds)
a (acceleration) = 2.1 m/s²
Solving:










Answer:
<span>
C. 5.3s</span>
Answer:
Diffusion time is 7.42 h
Solution:
As per the question:
Temperature, T = 
Surface concentration of arsenic, 
Surface concentration below Silicon surface, 
D = 
x = 
Initial concentration at t = 0, 
Now, by using Flick's second eqn:

Thus by putting appropriate values:

(1)
Now,

Now, from error function values tabulation:
For z = 2.0, erf(z) = 0.998
For z = 2.2, erf(z) = 0.995
Now,
With the help of linear interpolation method:

z = 2.12
Now, using eqn (1) and above value:

= 26700 s
t =