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3 years ago

What type of specialized cell in the eye is used for detecting low levels of light?

Physics

2 answers:

Hunter-Best [27]3 years ago

8 0

Answer:

There are about six to seven million cones in a human eye and are most concentrated towards the macula. Cones are less sensitive to light than the rod cells in the retina (which support vision at low light levels), but allow the perception of color.

pashok25 [27]3 years ago

8 0

Answer:

Rods

Explanation:

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What countries could benefit most from solar energy

Alecsey [184]

Countries longer day for example in the Middle East could benefit more but Alaska has more night like longer night which is why it would hard to benefit from the solar panels there.

Hoped this helped

5 0

2 years ago

A gas takes up a volume of 17.0 L, has a pressure of 2.30 atm, and a temperature of 299 K. If the temperature is raised to 350.0

Maurinko [17]

Answer:

new volume = 30.513L

Explanation:

V1 =17L , P1= 2.3atm , T1=299K , T2=350K , P2 =1.5atm, V2=?

To find the new volume of the gas we will use the combined gas law.

The combined gas law combines Boyle's law, Charles law and Gay-Lussac's law. Its states that the ratio of the product of pressure and volume to temperature is equal to a constant. its expressed mathematically below.

$\frac{V1P1}{T1} = \frac{V2P2}{T2}$

$V2 =\frac{V1P1T2}{P2T1}$

$V2 =\frac{17*2.3*350}{1.5*299}$

$v2 = \frac{13685}{448.5}$

V2 =30.513L

4 0

3 years ago

Read 2 more answers

Bill steps off a 3.0-m-high diving board and drops to the water below. At the same time, Ted jumps upward with a speed of 4.2 m/

Pani-rosa [81]

Answer:

equation of motion for Bill is

$y(t) = 4.9t^2$

equation of motion for Ted is

$y(t) = 2 + (-4.2)(t) + 4.9t^2$

Explanation:

Taking downward position positive and upward position negative

g = 9.8 m/s^2

equation of motion for Bill is

$y(t) = y_0 +v_0 t +\frac{1}{2}gt^2$

$y(t) = 0 + 0(t) +\frac{1}{2}gt^2$

$y(t) = \frac{1}{2}\times (9.8t)^2$

$y(t) = 4.9t^2$

equation of motion for Ted is

$y_0 = 2m -1m = 2m$

$y_0 = -4.2 m/s$

$y(t) = y_0 +v_0 t +\frac{1}{2}gt^2$

$y(t) = 2 + (-4.2)(t) +\frac{1}{2}gt^2$

$y(t) = 2 + (-4.2)(t) +\frac{1}{2}\times (9.8t)^2$

$y(t) = 2 + (-4.2)(t) + 4.9t^2$

8 0

3 years ago

Read 2 more answers

When a 72 W light bulb is connected to a 298 V source, what is the current ?

Norma-Jean [14]

the current is 0.24 Amperes

Explanation

power is the amount of energy transferred or converted per unit time, it can be found using the formula

$\begin{gathered} P=I*V \\ where\text{ P is the power} \\ I\text{ is the current} \\ V\text{ is the voltage} \end{gathered}$

Step 1

a)let

$\begin{gathered} P=\text{ 72 Watts} \\ V=298\text{ V} \end{gathered}$

b) now, replace in the formula and solve for I

$\begin{gathered} P=I*V \\ 72\text{ W=I*298 V} \\ divide\text{ both sides by 298 V} \\ \frac{72W}{298\text{ V}}\text{=}\frac{I*298V}{298\text{ V}} \\ 0.24\text{ Amperes=I} \end{gathered}$

therefore,the current is 0.24 Amperes

I hope this helps you

6 0

1 year ago

Q|C A lightbulb marked "75 W [at] 120 V " is screwed into a socket at one end of a long extension cord, in which each of the two

VashaNatasha [74]

The actual power that is delivered to this lightbulb would be less than 75 Watts due to resistance of the conducting wires. Consequently, the resistance of these conducting wires would cause a voltage drop and as such reducing the power.
The circuit diagram for the connection of this lightbulb is shown in the image attached below.
The actual power delivered to this lightbulb is equal to 73.8 Watts.

<h3>How to calculate the power delivered to the lightbulb?</h3>

Mathematically, the power delivered to this lightbulb can be calculated as follows by using this formula:

Power, P = IV

Where:

I represents the current.

V represents the voltage.

Basically, the actual power that is delivered to this lightbulb would be less than 75 Watts due to resistance of the conducting wires. Consequently, the resistance of these conducting wires would cause a voltage drop and as such reducing the power.

Also, the circuit diagram for the connection of this lightbulb is shown in the image attached below.

<h3>How to determine the actual power delivered to this lightbulb?</h3>

First of all, we would determine the resistance in this electrical circuit:

P = IV = V²/R

R = V²/P

R = 120²/75

Resistance, R = 192 Ohms.

For the total equivalence resistance, we have:

Total equivalence resistance = 0.8 + 0.8 + 192

Total equivalence resistance = 193.6 Ohms.

Next, we would determine the current in this electrical circuit by applying Ohm's law:

V = IR

I = V/R

I = 120/193.6

Current, I = 0.62 Ampere.

Now, we can calculate the actual power delivered to this lightbulb:

P = I²R

P = 0.62² × 192

Actual power, P = 73.8 Watts.

Read more on actual power here: brainly.com/question/13896943

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<u>Complete Question:</u>

A lightbulb marked "75 W [at] 120 V" is screwed into a socket at one end of a long extension cord, in which each of the two conductors has resistance 0.800 V. The other end of the extension cord is plugged into a 120-V outlet.

(a) Explain why the actual power delivered to the lightbulb cannot be 75 W in this situation.

(b) Draw a circuit diagram.

3 0

2 years ago