Answer:
Step-by-step explanation:
we know that
----> by trigonometric identity
we have
substitute
Remember that
If the sine of angle theta is positive, then the angle theta lie on the I Quadrant or II Quadrant
therefore
If the angle theta is on the I Quadrant the cosine will be positive
If the angle theta is on the II Quadrant the cosine will be negative
Answer:
Please see the attached picture for the full solution.
*From the 4th line of the 1st image, you could also expand it using
(a +b)²= a² +2ab +b² and
(a -b)²= a² -2ab +b².
When squaring a fraction, square both the denominator and numerator.
➣(a/b)²= a²/b²
Answer:
you graph it
Step-by-step explanation:
put it in yo cal
Selections B and D both appear to be appropriate.
B) (x+8)² + (y+5)² = 13
D) (x+8)² + (y+5)² = 13
_____
The center is at the midpoint of the diameter, ((-10-6)/2, (-8-2)/2) = (-8, -5). For center (h, k) and radius r, the equation is
(x -h)² +(y -k)² = r²
(x -(-8))² +(y -(-5))² = (√13)²
(x+8)² + (y+5)² = 13
