How can u turn 10 into a mixed number ?

Find the slope of a line that goes through point A(8,-4) and C(2, -1)

Black_prince [1.1K]

The answer for finding the slope is -1/2

5 0

3 years ago

if you were to solve the following system by substitution what would be the best variable to solve and from what equation? 2x+8y

Nina [5.8K]

All the numbers in the first equation have a common factor of 2. Removing that gives
.. x +4y = 6
making it easy to solve for x
.. x = 6 -4y

My choice would be to solve for x using the first equation.

_____
On second thought, it might actually be easier to solve either equation for 8y. That term then directly substitutes into the other equation (equivalent to adding the two equations).
.. 8y = 3x -11 . . . . . from the second equation
.. 2x +(3x -11) = 12 . . . substituting into the first equation
.. 5x = 23 . . . . . . . . . . collect terms, add 11 (what you would get by adding the equations in the first place)
.. x = 4.6
.. y = (3*4.6 -11)/8 = 0.35

4 0

4 years ago

A line y intercept is 2 and it's slope is 2 what is its equation in slope intercept form

Alenkinab [10]

Answer:

y = 2x+2

Step-by-step explanation:

y = mx+b

m = slope = 2

b = y-intercept = 2

7 0

2 years ago

Whats is the answer to this question below?

uysha [10]

Hey there. So first we need to know what the point slope form looks like.

It is Y-Y1=M (X-X1)

Knowing this you just plug in the given information.

M is equal to 1/6. So in this case all of the options have the correct m. Next we look at the Year value. We know Y is a positive 4. So the beginning of the equation is going to look like

Y+4=1/6 ( X-X1).

Nown plug in x. It would be a negative 5. Now your final answer would be option A. Hope the explanation helped.. :)

4 0

3 years ago

Suppose 300 nursing students took a certification test that is worth 100 points.

Alja [10]

Answer:

225 students scored 65 or better and 75 students scored 88 or better.

Step-by-step explanation:

We are given that The five-number summary for the scores of 300 nursing students are given :

Minimum = 40

$Q_1 = 65$

Median = 82

$Q_3 = 88$

Maximum = 100

$Q_1$ is the first quartile and is the median of the lower half of the data set. 25% of the numbers in the data set lie below $Q_1$ and about 75% lie above $Q_1$ .

$Q_3$ is the third quartile and is the median of the upper half of the data set. 75% of the numbers in the data set lie below $Q_3$ and about 25% lie above $Q_3$

i) .About how many students scored 65 or better?

$Q_1 = 65$

Since we know that 75% lie above $Q_1$ .

So, Number of students scored 65 or better = $75\% \times 300 = \frac{75}{100} \times 300 =225$

ii)About how many students scored 88 or better?

$Q_3 = 88$

Since we know that 25% lie above $Q_3$

So, Number of students scored 88 or better = $25\% \times 300 = \frac{25}{100} \times 300 =75$

Hence 225 students scored 65 or better and 75 students scored 88 or better.

7 0

3 years ago