First term is -7, so a_1 = -7
To get the next term, we add on 4. We can see this if we subtract like so
d = (2nd term) - (1st term) = (-3) - (-7) = -3+7 = 4
So d = 4 is the common difference.
Apply a_1 = -7 and d = 4 to get...
a_n = a_1 + d*(n-1)
a_n = -7 + 4*(n-1)
a_n = -7 + (n-1)*4
Answer: Choice A
The slope would have to be -3
The measure of FHG is 64°.
Answer:
Part 1
a. .27 < .50
b. .33 < .75
c. 4.60 > 3.89
d. .76 > .08
e. .09 < .11
f. 3.33 > 3.30
Part 2
.27(2)= .54
.50(1)= .50
.27(2)= .54 is larger than .50 because if it was money, .54 is greater than .50
Step-by-step explanation:
Answer:
2472 students
Step-by-step explanation:
<u>What we know:</u>
- There are 6 schools
- Each school has 412 students
<u>What we're trying to solve:</u>
How many students are there altogether?
To find this, we multiply 412 by 6. Doing this is essentially the same as adding 412 to itself 6 times for each school there is in the district.
412 students × 6 schools
= 2472 students
Therefore, there are 2472 students in the district.
I hope this helps!
