Take all three trial result averages and add them up
Then take that number and divide by three because there was three numbers added.
That number is the average of the three trials
53x12=636 that is your answer that is the way to estimate it your answer is 636 that is how many students can be seated
The mean is the average so 180/50 = 3.6 therefor the mean of each donation from each sponsor is £3.60
Step One
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Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
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Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Answer:
2.92
Step-by-step explanation:
![V=\frac{4}{3}\pi r^3 \\ \\ 105=\frac{4}{3}\pi r^3 \\ \\ r^3=\frac{105}{\frac{4}{3}\pi} \\ \\ r=\sqrt[3]{\frac{105}{\frac{4}{3}\pi}} \\ \\ r \approx 2.92](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3%20%5C%5C%20%5C%5C%20105%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3%20%5C%5C%20%5C%5C%20r%5E3%3D%5Cfrac%7B105%7D%7B%5Cfrac%7B4%7D%7B3%7D%5Cpi%7D%20%5C%5C%20%5C%5C%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cfrac%7B4%7D%7B3%7D%5Cpi%7D%7D%20%20%5C%5C%20%5C%5C%20r%20%5Capprox%202.92)
