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Elden [556K]
3 years ago
6

The graph shows y as a function of x: In which segment is the function constant?

Mathematics
2 answers:
erastova [34]3 years ago
5 0
Q because it’s at a straight level
Alla [95]3 years ago
5 0
It’s Q because it goes on for a bit and then it stops and goes down at R
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Cheryl spends 3/10 of her savings on a book and 2/5 of it on a pen. What fraction of her savings does Cheryl spend.
Musya8 [376]
7/10 is the answer k
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3 years ago
Read 2 more answers
Find the quadratic function y=​f(x) whose graph has a vertex ​(−3​,4​) and passes through the point ​(−7​,0). Write the function
olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.  

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

a=-\frac{1}{4}

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

And there you go!

5 0
3 years ago
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The answer is easy
So we need to fund m2NLM
The answer is c
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2 years ago
How do you determine if a given set of measurements works for the side lengths of a triangle? (It should be a number)
zaharov [31]
Add them all up and if they add up to 180 then your side lengths are good
5 0
3 years ago
After a reflection over the line x-axis, (8,11) is the image of point C. What is the original location of point C.
goblinko [34]
(-8, -11) because the points are just the opposite sign when reflecting over the x-axis
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2 years ago
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