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3 years ago

Which is the most accurate way to estimate 26% of 91?

Mathematics

1 answer:

notka56 [123]3 years ago

8 0

Answer:

Step-by-step explanation:

26% is close to 25%, which is equal to 1/4th.

You're adding to the number and removing from the percentage so it balances it out.

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When looking at the median of a data set, what information do you get when looking at the median?

cestrela7 [59]

You get the middle of all the data while looking at the median of a data set!

I hope this helped! Mark me Brainliest! :) -Raven❤️

7 0

3 years ago

(07.09) Jonah is purchasing a car that is on sale for 15% off. He knows the function that represents the sale price of his car i

atroni [7]

Answer:

Answer: f[c(p)] = 0.9265p

Step-by-step explanation:

Given: Jonah is purchasing a car that is on sale for 15% off. He knows the function that represents the sale price of his car is , where p is the original price of the car.

He also knows he has to pay 9% sale's tax on the car. The price of the car with tax is , where c is the sale price of the car.

Now, the composite function that can be used to calculate the final price of Jonah's car is given by :-

3 0

3 years ago

Read 2 more answers

How to do a line plot to the nearest fourth inch

Shalnov [3]

Just count, its really simple...its hard to explain using a keyboard tho...sorry i wasnt much help

6 0

4 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

3 years ago

Carol drives her daughter to school at an average rate of 30 miles per hour, but only goes an average rate of 20 miles per hour

Ivahew [28]

<span>24 mph

</span>P.S. please vote this as the brainliest answer :)

6 0

3 years ago