Which is the correct rule to use when converting the complex number z = a + bi to polar coordinates?

Mathematics

1 answer:

Kobotan [32]2 years ago

3 0

The correct rule is the range of eligibility of evocative

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Li bought his dog Spot a huge bone that is 15 inches long. Spot chews 4 inches off the bone every day. What is the new length of

kap26 [50]

Answer:

3 inches

Step-by-step explanation:

If the dog chews off 4 inches every day, you first have to multiply the inches by the number of days, which in this case is 3 x 4, which equals 12. In 3 days, he chewed off 12 of the original 15 inches, leaving only 3 inches left.

3 0

3 years ago

Find vÌ, the orthogonal projection of v onto w. you can't enter vÌ as a variable name in matlab, so call it vbar instead. also c

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3 years ago

Compute the slope of the line intersecting the points (1, 2) and (3, 8). *

DiKsa [7]

Answer:

slope = 3

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (1, 2) and (x₂, y₂ ) = (3, 8)

m = $\frac{8-2}{3-1}$ = $\frac{6}{2}$ = 3

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3 years ago

3.01(the 1 is repeating)as a mixed number

Masteriza [31]

The quick and easy answer is 3/100

7 0

4 years ago

PLEASE HELP!!! Find the equation , in the standard form of the line passing through the points (3,-4) and (5,1)

ExtremeBDS [4]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 3 &,& -4~) 
% (c,d)
&&(~ 5 &,& 1~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-4)}{5-3}\implies \cfrac{1+4}{5-3}\implies \cfrac{5}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{5}{2}(x-3)\implies y+4=\cfrac{5}{2}x-\cfrac{15}{2}$

$\bf y=\cfrac{5}{2}x-\cfrac{15}{2}-4\implies y=\cfrac{5}{2}x-\cfrac{23}{2}\impliedby 
\begin{array}{llll}
\textit{now let's multiply both}\\
\textit{sides by }\stackrel{LCD}{2}
\end{array}
\\\\\\
2(y)=2\left( \cfrac{5}{2}x-\cfrac{23}{2} \right)\implies 2y=5x-23\implies \stackrel{standard~form}{-5x+2y=-23}
\\\\\\
\textit{and if we multiply both sides by -1}\qquad 5x-2y=23$

side note: multiplying by the LCD of both sides is just to get rid of the denominators

5 0

3 years ago