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Likurg_2 [28]
2 years ago
14

Help pleaseeeeeeeeee​

Mathematics
1 answer:
ad-work [718]2 years ago
4 0

Answer:

non of these choices I guess

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Rebecca already knew 1 appetizer recipe before starting culinary school, and she will learn 3
Ostrovityanka [42]

Answer:

14 weeks

Step-by-step explanation:

so from what we know she already learned one appetizer recipe so she needs to learn 42 more so what we need to do since it's three every week we need to multiply three until we are able to get 42 so three times 14 gets 42 so that means that the answer would be 14

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The triangles are not congruent.

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2 years ago
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faust18 [17]

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3 can go into 77  25 times.

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3 years ago
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kolezko [41]
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4 0
3 years ago
An electronic product contains 48 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the
BigorU [14]

Answer:

0.6173 = 61.73% probability that the product operates.

Step-by-step explanation:

For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

An electronic product contains 48 integrated circuits.

This means that n = 48

The probability that any integrated circuit is defective is 0.01.

This means that p = 0.01

The product operates only if there are no defective integrated circuits. What is the probability that the product operates?

This is P(X = 0). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{48,0}.(0.01)^{0}.(0.99)^{48} = 0.6173

0.6173 = 61.73% probability that the product operates.

5 0
3 years ago
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