What is the standard form when your ordered pairs are (4,5) and your slope is 5/4?

1 answer:

3 0

The slope (m) and the ordered pairs are given.
In order to arrive at the standard form : AX + BY = C, we need to form the slope-intercept form first : y = mx + b

Substitute the values in order to get the intercept (b)
y = mx + b
5 = 5/4 * 4 + b
5 = 5 + b
b = 0

So given the m = 5/4, b = 0
y = mx + b
y = 5/4x+ 0

Converting it to Standard Form
y = 5/4x + 0
5/4x - y = 0 (multiply both sides by 4)
5x - 4y = 0

<span>So the Standard form is 5x - 4y = 0</span>

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What is the value of C in the matrix equation below?

lara [203]

Given:

The matrix equation is:

$\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}$

To find:

The value of matrix C.

Solution:

Let $A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}$ . Then the given equation can be rewritten as

$A-C=B$

$-C=B-A$

$C=-(B-A)$

$C=A-B$

On substituting the values of the matrices, we get

$C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}$

$C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}$

$C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}$

$C=\begin{bmatrix}-4&2&-7\end{bmatrix}$

Therefore, the correct option is C.

6 0

2 years ago

Read 2 more answers

he graph represents function 1, and the equation represents function 2: A coordinate plane graph is shown. A horizontal line is

Reika [66]

Answer:

The answer is 2

Step-by-step explanation:

Rate of change of function is given by :

$\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}$

For function y = 6,

rate of change =

$=\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}\\=\frac{6-6}{x_{2}-x_{1}}\\=0$

because the function is independent of x.

For function y = 2·x + 7,

rate of change =

$=\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}\\=\frac{2\cdot x_{2}+7-2\cdot x_{1}-7}{x_{2}-x_{1}}\\=\frac{2\cdot x_{2}-2\cdot x_{1}}{x_{2}-x_{1}}\\=\frac{2\cdot (x_{2}-x_{1})}{x_{2}-x_{1}}\\=2$