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2 years ago

Question 1 Which is the largest value?

Mathematics

1 answer:

barxatty [35]2 years ago

7 0

Answer:

the third option 6 squareroot of 5 would be the largest value

Step-by-step explanation:

3 squareroot of 7 is also 63 squareroot

5 squareroot of 3 is also 75 squareroot

6 squareroot of 5 is also 180 squareroot

2 squareroot of 8 is also 32 squareroot

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Graph the solution of the inequality –3(x + 1) ≤ 6 on the number line.

fomenos

First you solve the inequality. Add the variables that can be added together. That would be -3 + 1=2. Now the equation is 2 + x<6. After you change the 2 into a negative and put it under the 6 and subtract. that is 3. 3 is the number you put on the number line. When you fine and plot three you make a dot above it. You fill in the dot since the less then sign has a line beneath it. Then you draw a line from the dot to the end of the number line from the direction the sign is facing. It’s a less then sign, so you would draw the line to the left.

3 0

3 years ago

Find the equation of the circle whose center is at (4, 5) and that contains (13, −1).

zepelin [54]

The equation of circle is
(x-4)^2+(y-5)^2=R^2
if you replace the (13, -1) with x and y the R^2 will be 117
(x-4)^2+(y-5)^2=117

3 0

3 years ago

E Homework: 3.1 Homework

LenKa [72]

The given function is f(z)=3z-8 for the values f(-4), f(2) and f(z-7) respectively -20, -2 and 3z-29 respectively.

The given function is f(z)=3z-8.

We need to find the value of f(-4), f(2), f(z-7).

<h3>What is a function?</h3>

In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

Now to find f(-4), replace z from -4.

f(-4)=3(-4)-8=-12-8=-20

Now to find f(2), replace z from 2.

f(2)=3(2)-8=6-8=-2

Now to find f(z-7), replace z from z-7.

f(z-7)=3(z-7)-8=3z-21-8=3z-29.

Therefore, the given function is f(z)=3z-8 for the values f(-4), f(2) and f(z-7) respectively -20, -2 and 3z-29 respectively.

To learn more about functions visit:

brainly.com/question/21145944.

#SPJ1

4 0

2 years ago

Select either relation (if the set is a relation but not a function), function (if the set is both a relation and a function), o

galina1969 [7]

Answer: The correct options are

(A) relation

(B) function.

Step-by-step explanation: We are given to check whether the following set is a relation or a relation and a function or neither :

A = {(1, 2) (2, 2) (3, 2) (4, 2)} .

Let us consider the following two sets :

U = {1, 2, 3, 4} and V = {2}.

Then, we see that the Cartesian Product of U and V is given by

U × V = {(1, 2) (2, 2) (3, 2) (4, 2)}.

Since a relation is a subset of Cartesian product, so the given set A is a relation.

Also, we know that a relation is a function if every first element is associated with one second element.

Since the relation A satisfies this condition, so the relation A is a function.

Thus, the given set A is both a relation and a function.

Option (A) and (B) are correct.

6 0

3 years ago

a. Verify that the given point lies on the curve. b. Determine an equation of the line tangent to the curve at the given point.

xxMikexx [17]

Answer:

y = 13*( -x/9 + 1/5)

Step-by-step explanation:

Given:

- The curve has an equation as follows:

$44 = 5x^2 + 3xy + 3y^2$

Find:

a. Verify that the given point (2,2) lies on the curve.

b. Determine an equation of the line tangent to the curve at the given point.

Solution:

- To verify whether the point lies on the given curve we will substitute the coordinates of the point into the equation as follows:

44 = 5*(2)^2 + 3*(2)(2) + 3*(2)^2

44 = 20 + 12 + 12

44 = 44 ......Hence proven.

- The equation of the line tangent to the curve is expressed as a linear function as follows:

y = m*x + C

Where, m is the gradient of the line.

C is the y-intercept.

m = Δy / Δx = dy/dx

- We will take the derivative of the given curve with respect to x as follows:

$0 = 10x + 3*( y + xy' ) + 6y*y'\\\\-10x - 3y = y' ( 3x + 6y)\\\\ y' = - \frac{10x + 3y}{3x + 6y}$

- Evaluate y' at the point (2,2) we get:

y' = - ( 10(2) + 3(2) ) / ( 3(2) + 6(2) )

y' = - ( 26 ) / (18)

y'= m = - 13/9

- To evaluate C, we will use the point (2,2) for linear expression above with m as follows:

y = -13*x/9 + C

2 =-13*(2)/9 + C

C = 13 / 5

- The equation of the tangent is as follows:

y = 13*( -x/9 + 1/5)

8 0

3 years ago