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topjm [15]
3 years ago
9

The temperature 6:00 pm was 24 Fahrenheit. At midnight the temperature was 36 Fahrenheit lower than 6:00 pm what was the tempera

ture at midnight ?
Mathematics
1 answer:
MariettaO [177]3 years ago
4 0

Answer:

tjjfjfjfjfjfjfjjfjfjfjffjj

Step-by-step explanation:

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In a video game, two objects move around the screen according to the equations r = 4cos(0) and r= -1 +
Ugo [173]

Answer:

The correct option is;

\left ( -2,\dfrac{2 \cdot \pi }{3} \right)

Step-by-step explanation:

The given parameters are

The equation of motion of one (the first) object is r = 4·cos(θ)

The equation of motion of the other (the second) object is r = -1 + 2·cos(θ)

Equating both equations gives;

4·cos(θ) = -1 + 2·cos(θ)

4·cos(θ) - 2·cos(θ) = -1

2·cos(θ) = -1

cos(θ) = -1/2

θ = Arccos(-1/2) = 120° = 2·π/3

Therefore, the two equations are equal when θ = 2·π/3 for which we have;

r = 4·cos(2π/3) = -2 and r = -1 + 2·cos(2π/3) = -2

∴ r = 4·cos(2π/3) = -1 + 2·cos(2π/3) = -2

The coordinate that represents a possible collision point of the objects in the form (r, θ) is therefore \left ( -2,\dfrac{2 \cdot \pi }{3} \right)

8 0
3 years ago
Read 2 more answers
Find the coordinates of the point Q on the X-axis which lies on the perpendicular bisector of the line joining the points A ( -5
OleMash [197]
The coordinates of Q would be (-1/2,0) and it would be a isosceles triangle.
8 0
3 years ago
The Chiquita Bananas are on sale for $3.72 for 6 pounds of bananas. Miller's Bananas are on sale for $0.64 per pound. Which comp
puteri [66]

Answer:

millers is cheper instead of 3.72 for 6 pond 0.64 is better because what if some one only wants 1 pond then they only should pay 64 cents

Step-by-step explanation:

3 0
3 years ago
I’ll award brainliest! no links
tensa zangetsu [6.8K]
YZ=8.66 see pic for work

7 0
3 years ago
Area of the grass area only:<br><br> Area of the track only:
VikaD [51]

Answer:

Step-by-step explanation:

area including track=area of 2 semi circles+area of rectangle

=2×1/2×π×46²+86×65

=2116 π+5590

area of grass=2×1/2×π×40²+80×65=1600π+5200

≈10226.55 m²

area of track=2116π+5590-1600π-5200

=516π+390

≈2011.06 m²

7 0
3 years ago
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