5 (2f+3)=2(5f-1)
10f+15=10f-2
10f-10f=-2-15
f=-17
Answer:
The answers are that a = -5 and b = 1
Step-by-step explanation:
In order to find A and B, we first need to find the equation of the line. We can do this by using two ordered pairs and the slope formula. For the purpose of this activity, I'l use (0, 5) and (-3, 11)
m(slope) = (y2 - y1)/(x2 - x1)
m = (11 - 5)/(-3 - 0)
m = 6/-3
m = -2
Now that we have this we can model this using point-slope form.
y - y1 = m(x - x1)
y - 5 = -2(x - 0)
y - 5 = -2x
y = -2x + 5
Now that we have the modeled equation we can use the ordered pair (a, 15) to solve for a.
y = -2x + 5
15 = -2(a) + 5
10 = -2a
-5 = a
And we can also solve for b using the ordered pair (2, b)
y = -2x + 5
b = -2(2) + 5
b = -4 + 5
b = 1
Answer:
See explanation
Step-by-step explanation:
1. From the graph of absolute value function:
a. The domain is 
b. The range is 
c. The graph is increasing for all 
d. The graph is decreasing for all 
2. From the graph of quadratic function:
a. The domain is
b. The range is ![y\in (-\infty,0]](https://tex.z-dn.net/?f=y%5Cin%20%28-%5Cinfty%2C0%5D)
c. The graph is increasing for all
d. The graph is decreasing for all
Answer:
y = -1/3x + 1/3
Step-by-step explanation:
x+3y=2
3y = 2 - x
y = 2/3 - 1/3x
y = -1/3x +2/3
the slope is -1/3 and the equation that is parallel will have the same slope also
y = mx + b
y = -1/3x + b
0 = -1/3(1) + b
0 = -1/3 + b
1/3 = b
y = -1/3x + 1/3
