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2 years ago

%7D%7Bquiz%20%5C%3A%20%20%5C%3A%20%7D%7B%20%7B%7B%5Cboxed%7B%5Ccolor%7Baqua%7D%7B3%20%5Ctimes%203%20%2B%20654%20-%203%20%5Ctimes%2043%20%5Cdiv%204%20%2B%2066666%20-%20366%20%5Ctimes%2033%20%5Cdiv%2033%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D" id="TexFormula1" title="\small{\colorbox{black}{\red{\boxed{{ \sf\: \color{hotpink}{quiz \: \: }{ {{\boxed{\color{aqua}{3 \times 3 + 654 - 3 \times 43 \div 4 + 66666 - 366 \times 33 \div 33}}}}}}}}}}" alt="\small{\colorbox{black}{\red{\boxed{{ \sf\: \color{hotpink}{quiz \: \: }{ {{\boxed{\color{aqua}{3 \times 3 + 654 - 3 \times 43 \div 4 + 66666 - 366 \times 33 \div 33}}}}}}}}}}" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

JulijaS [17]2 years ago

5 0

Answer:

67,296.75

Step-by-step explanation:

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600kb in 24 seconds to find out how many kbs per second divide by 24
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3 years ago

Which are the solutions of x^2 = –11x + 4?

strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

$x^2 + 11x - 4 = 0$

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

$x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}$

where $x_{1,2}$ is a compact way to indicate both solutions $x_1$ and $x_2$ , while $a,b,c$ are the coefficients of the quadratic equation, i.e. we consider the polynomial $ax^2+bx+c$ .

So, in your case, we have $a=1,\ \ b=11,\ \ c=-4$

Plug those values into the formula to get

$x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}$

So, the two solutions are

$x_1 = \frac{-11+\sqrt{137}}{2}$

$x_2 = \frac{-11-\sqrt{137}}{2}$