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UNO [17]
3 years ago
13

Please help fast! give me the equation

Mathematics
1 answer:
uranmaximum [27]3 years ago
6 0

\begin{bmatrix}x=\frac{\pi }{2}+2\pi n\\ x=\frac{3\pi }{2}+2\pi n\\ x=\frac{3\pi }{4}+\pi n\\ x=\frac{7\pi }{4}+\pi n\end{bmatrix}

\begin{bmatrix}\frac{3\pi }{2}+2\pi n=\frac{\pi }{2}+2\pi n\\ \frac{3\pi }{2}+2\pi n=\frac{3\pi }{4}+\pi n\\ \frac{3\pi }{2}+2\pi n=\frac{7\pi }{4}+\pi n\end{bmatrix}

\pi =0

- hope this helps! -

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the 30th term is 239

Step-by-step explanation:

The computation of the 30th term is as follows:

As we know that

a_n = a_1 + (n-1)d

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Now based on this, the 30th term is

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Hence, the 30th term is 239

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Step-by-step explanation:

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

x + y = 2

y = 5

<u>Step 2: Solve for </u><u><em>x</em></u>

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3 years ago
A research firm conducted a study to determine the average amount of money that smokers spend on cigarettes during a week. The f
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Answer:

0.9544 = 95.44% probability that a new sample this year of 100 steady smokers spends between $19 and $21 on average

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The firm found that the population mean amount that all smokers spend on cigarettes is $20 and the population standard deviation is $5.

This means that \mu = 20, \sigma = 5

Sample of 100:

This means that n = 100, s = \frac{5}{\sqrt{100}} = 0.5

What is the probability that a new sample this year of 100 steady smokers spends between $19 and $21 on average?

This is the pvalue of Z when X = 21 subtracted by the pvalue of Z when X = 19. So

X = 21

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{21 - 20}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 19

Z = \frac{X - \mu}{s}

Z = \frac{19 - 20}{0.5}

Z = -2

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that a new sample this year of 100 steady smokers spends between $19 and $21 on average

3 0
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