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ivann1987 [24]
3 years ago
8

Did I do it right? Please help ASAP!

Mathematics
1 answer:
Naddik [55]3 years ago
4 0

Answer:yes

Step-by-step explanation:

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ashley purchased a prepaid card phone card for $15. long distance calls cost 11 cents per minute using this card. ashley used he
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It depends if Ashley was on the call for seconds too,if there can be a remainder , if so then it would be 3 min. and 47 sec.
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Please help me (Will give brainliest)
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This is very similar to the last question:-

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4 years ago
The x-axis contains the base of an equilateral triangle RST. The origin is at S. Vertex T has coordinates (2h, 0) and the y-coor
frosja888 [35]
For the first part remember that an equilateral triangle is a triangle in which all three sides are equal & all three internal angles are each 60°. <span>So x-coordinate of R is in the middle of ST = (1/2)(2h-0) = h
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7 0
4 years ago
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Convert the following sum into a product. cosx + cos3x + cos5x + cos7x
kvv77 [185]

Answer:

4\cos x\cos (4x)\cos (2x)

Step-by-step explanation:

Given: cosx + cos3x + cos5x + cos7x

To convert: the given sum into product

Solution:

Use formula: \cos A+\cos B=2\cos \left ( \frac{A+B}{2} \right )\cos \left ( \frac{A-B}{2} \right )

cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos (2x)\cos (-x)+2\cos (6x)\cos (-x)\\=2\cos (2x)\cos (x)+2\cos (6x)\cos (x)\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]

cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]\\=2\cos x\left [2 \cos \left ( \frac{2x+6x}{2} \right )\cos \left ( \frac{2x-6x}{2} \right ) \right ]\\=2\cos x\left [ 2\cos (4x) \cos (-2x) \right ]\\=4\cos x\cos (4x)\cos (2x)

4 0
3 years ago
Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseb
gregori [183]
Using the inequality
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 x = 6.4
The maximum number of hamburgers he can sell is 6
5 0
3 years ago
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