Answer:
p=0.9
Explanation:
The frequency of the different genotypes is as follows:
- AA = 0.81
- Aa = 0.18
- aa = 0.01
There are 2 alleles for this gene, the dominant allele <em>A</em> appears twice in the homozygous dominant genotype and once in the heterozygous.
Then, the frequency of the <em>A </em>allele, <em>p</em>, can be calculated as:
p= freq(AA) + freq(Aa)/2
p= 0.81 + 0.18/2
p=0.9
They both may have gone to a chilly area from their instincts.
The answer to your question is:
C. 22 pairs of autosomal chromosomes, 1 X chromosome, and 1 Y chromosome.
I hope this helps!
