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Allisa [31]
3 years ago
10

Whats the measure of the angle 2x 10=x-10

Mathematics
1 answer:
mojhsa [17]3 years ago
3 0
To solve, we use the fact that W = X + Y. Note that here I'm referring to the angles W, X, and Y as shown in the first image of this lesson. Their names are not important. What is important is that an exterior angle equals the sum of the remote interior angles.
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Given the right triangle ABC, find tan A​
EleoNora [17]

The tangent is the ratio of the perpendicular and the base of the right triangle. Then tan A will be x/y.

<h3>What is trigonometry?</h3>

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The right-angle triangle ΔABC is given.

The angle ∠C is 90°.

And the perpendicular is x, the base is y, and the hypotenuse is z.

Then the value of the tangent of angle ∠A will be

The tangent is the ratio of the perpendicular and the base of the right triangle.

tan A = x/y

More about the trigonometry link is given below.

brainly.com/question/22698523

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4 0
2 years ago
$1,672.68<br> $287.84<br> $12.32
Andrei [34K]

Answer:

$1672.68

Step-by-step explanation:

4 0
3 years ago
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Guys please help me with this question, I’d appreciate it a lot
vredina [299]
The answer is 435 :)
3 0
3 years ago
What is h(x) when x=1.5​
VARVARA [1.3K]
It is just telling you to replace all of the x’s with 1.5 and then solve the equation
6 0
3 years ago
the numerator of a fraction x/y is 2 less than the denominator. If 3 is added to both the numerator and denominator, then the su
Mashutka [201]

Answer:

Step-by-step explanation:

Fraction :x/y

numerator x = y - 2

Now the fraction can be written as: (y-2)/y

3 is added to both denominator and numerator.

After adding 3, the new fraction = \frac{y-2 +3 }{y + 3 } = \frac{y+ 1 }{y +3}

The sum of the new fraction and the original fraction is 53/35

\frac{y+1}{y+3} + \frac{y-2}{y} = \frac{53}{35}\\\\\frac{(y+1)*y}{(y+3)*y}+\frac{(y-2)*(y+3)}{y(y+3)}=\frac{53}{35}\\\\\frac{y^{2}+y}{y^{2}+3y}+\frac{y^{2}+y-6}{y^{2}+3y}=\frac{53}{35}\\\\\frac{y^{2}+y+y^{2}+y-6}{y^{2}+3y}=\frac{53}{35}\\\\\frac{2y^{2} + 2y - 6}{y^{2}+3y}=\frac{53}{35}\\\\

35*(2y² + 2y - 6) = 53 *(y² + 3y)

35*2y² + 2y * 35 - 6*35 = 53 *y² + 53*3y

70y² + 70y -  210 = 53y² + 159y

70y² + 70y -  210 - 53y² - 159y = 0

70y² - 53y² + 70y - 159y - 210 = 0

          17y²  - 89y - 210 = 0

6 0
3 years ago
Read 2 more answers
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