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Semmy [17]
3 years ago
10

All together, Dion and trevor worked a total of 38 hours last week. If Dion worked d hours, which expression represent the numbe

r of hours trevor worked?
Mathematics
1 answer:
Ahat [919]3 years ago
3 0

Answer:

You need to include more information.

Step-by-step explanation:


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I don’t really understand how to do this!!! Help plz
patriot [66]

Answer:

4

Step-by-step explanation:

It works with the second one

4 0
3 years ago
Help me!!! I need help ASAP
tia_tia [17]

9514 1404 393

Answer:

  y = 3.02x^3 -5.36x^2 +5.68x +8.66

Step-by-step explanation:

Your graphing calculator (or other regression tool) can solve this about as quickly as you can enter the numbers. If you have a number of regression formulas to work out, it is a good idea to become familiar with at least one tool for doing so.

__

If you're trying to do this by hand, the x- and y-values give you 4 equations in the 4 unknown coefficients.

  a·1^3 +b·1^2 +c·1 +d = 12

  a·3^3 +b·3^2 +c·3 +d = 59

  a·6^3 +b·6^2 +c·6 +d = 502

  a·8^3 +b·8^2 +c·8 +d = 1257

Solving this by elimination, substitution, or matrix methods is tedious, but not impossible. Calculators and web sites can help. The solutions are a = 317/105, b = -75/14, c = 1193/210, d = 303/35. Approximations to these values are shown above.

8 0
2 years ago
If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
2 years ago
What is the domain for the piece of the function represented by f(x) = x + 1?
love history [14]

Answer:

All real numbers

Step-by-step explanation:

The domain of the function represented by f(x) = x + 1 is the all real numbers as there is only addition involved in the function so putting any number as input will not lead the function to infinity.

6 0
3 years ago
Does anybody know this
Makovka662 [10]

Answer:

1) 75°

2)

3) 135°

4) 105°

7 0
3 years ago
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