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andrew11 [14]
3 years ago
12

HELP ASAP!!!!!! 20 Points and will mark brainliest for correct answer!

Mathematics
2 answers:
s2008m [1.1K]3 years ago
8 0
6x^2 - 2x = 7

6x^2 - 2x - 7 = 0

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

x = \dfrac{-(-2) \pm \sqrt{(-2)^2 - 4(6)(-7)}}{2(6)}

x = \dfrac{2 \pm \sqrt{4 + 168}}{12}

x = \dfrac{2 \pm \sqrt{172}}{12}

x = \dfrac{2 \pm 2\sqrt{43}}{12}

x = \dfrac{1 \pm \sqrt{43}}{6}
guapka [62]3 years ago
5 0
Hey there :)

6x² - 2x = 7

Bring all terms to one side and equate to 0
6x² - 2x - 7 = 0

Lets see if we can solve by factoring:
Sum = - 2  and   Product = - 7 
We do not have factors for this

Therefore, we need to solve by quadratic equation { Refer to the attached picture }

6x² - 2x - 7 = 0
 ↓      ↓     ↓
 a      b     c

x = \frac{-(-2)+/- \sqrt{(-2)^2-4(6)(-7)} }{2(6)}
x = \frac{2+/- \sqrt{ 172 } }{12} = \frac{2+/-2 \sqrt{43} }{12}

x = \frac{1+/-\sqrt{43}}{6}
         ↓
      Will be your answer



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2 years ago
Angle θ is in standard position. If (8, -15) is on the terminal ray of angle θ, find the values of the trigonometric functions.
nikitadnepr [17]

Answer:

* sin Ф = -15/17     * cos Ф = 8/17      * tan Ф = -15/8

* csc Ф = -17/15    * sec Ф = 17/8      * cot Ф = -8/15

Step-by-step explanation:

Lets revise the trigonometric function of angle Ф

- Angle θ is in standard position

- Point  (8, -15) is on the terminal ray of angle θ

- That means the terminal is the hypotenuse of a right triangle x and y

  are its legs

∵ x-coordinate is positive and y-coordinate is negative

∴ angle Ф lies in the 4th quadrant

- The opposite side of angle Ф is the y-coordinate of the point on the

  terminal ray of angle Ф and the adjacent side to angle Ф is the

  x-coordinate of that point

∵ The length of the hypotenuse (h) = √(x² + y²)

∴ h = √[(8)² + (-15)²] = √[64 + 225] = √[289] = 17

∴ The length of the hypotenuse is 17

- Lets find sin Ф

∵ sin Ф = opposite/hypotenuse

∵ The opposite is y = -15

∵ The hypotenuse = 17

∴ sin Ф = -15/17

- Lets find cos Ф

∵ cos Ф = adjacent/hypotenuse

∵ The adjacent is x = 8

∵ The hypotenuse = 17

∴ cos Ф = 8/17

- Lets find tan Ф

∵ tan Ф = opposite/adjacent

∵ The opposite is y = -15

∵ The adjacent = 8

∴ tan Ф = -15/8

- Remember csc Ф is the reciprocal of sin Ф

∵ csc Ф = 1/sin Ф

∵ sin Ф = -15/17

∴ csc Ф = -17/15

- Remember sec Ф is the reciprocal of cos Ф

∵ sec Ф = 1/ cos Ф

∵ cos Ф = 8/17

∴ sec Ф = 17/8

- Remember cot Ф is the reciprocal of tan Ф

∵ cot Ф = 1/tan Ф

∵ tan Ф = -15/8

∴ cot Ф = -8/15

5 0
3 years ago
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