Ask question

Ask question

All categories

1 year ago

13

the space station has an average orbit of 250 miles above the earth. how many pennies would it take to make a stack that high? p

lss show all work, ill give brainliest

1 answer:

KatRina [158]1 year ago

7 0

250 miles is 1 320 000 feet.

A penny is 0.005 feet tall.

You'd need 1 320 000 / 0.005 = 264 000 000 pennies to make a stack that high

You might be interested in

A line passes through the point (4,-9) and has a slope of -6. Write an equation in slope intercept form for this line

pishuonlain [190]

$\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{-9})~\hspace{10em} \stackrel{slope}{m}\implies -6 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-9)}=\stackrel{m}{-6}(x-\stackrel{x_1}{4}) \\\\\\ y+9=-6x+24\implies y=-6x+15$

6 0

2 years ago

I need help on this one thank you

lutik1710 [3]

The answer = B because of the pattern

6 0

2 years ago

Read 2 more answers

Lim 1 + cos TX<br>5.<br>x>1 tanưrex

Brums [2.3K]

Answer: 1/2

$\lim_{x \to 1}\frac{1+cos \pi x}{tan^{2}\pi x }\\\\ = \lim_{x \to 1} \frac{1+cos\pi x}{\frac{sin^{2}\pi x }{cos^{2}\pi x } } \\\\\\= \lim_{x \to 1}\frac{cos^{2}\pi x(1+cos\pi x) }{sin^{2}\pi x } \\\\\\= \lim_{x \to 1} \frac{cos^{2}\pi x(1+cos\pi x)}{1-cos^{2}\pi x } \\\\= \lim_{x \to 1} \frac{cos^{2}\pi x }{1-cos\pi x} \\\\= \lim_{x \to 1}\frac{cos^{2}\pi .1 }{1-cos\pi .1}\\\\= \lim_{x \to 1}\frac{1}{1-(-1)}\\\\=\frac{1}{2}$

Step-by-step explanation:

5 0

2 years ago

What the slope and y-intercept ?

Bond [772]

Answer:

slope = 2/1 or 2

the Y-intercept is 1

Step-by-step explanation:

Rise over run meaning count the rise (2) then the run (1)

5 0

2 years ago

Read 2 more answers

In the diagram shown below is it given (known) that FB and EH intersect at A and ZEAG is right. Give

djverab [1.8K]

Answer:

Angle HAB and Angle FAE are congruent angles

Step-by-step explanation:

we know that

Two angles are supplementary if their sum is equal to 180 degrees

In this problem

m∠FAH+m∠HAB=180° ----> by a linear pair

Remember that

A linear pair of angles is formed when two lines intersect. Two angles are said to be linear if they are adjacent angles formed by two intersecting lines. A linear pair of angles must add up to 180 degrees

m∠FAH+m∠FAE=180° ----> by a linear pair

therefore

m∠HAB=m∠FAE -----> by vertical angles

Angle HAB and Angle FAE are congruent angles

5 0

2 years ago