I am pretty sure you can only make one.
If two sides are known, and one of the angles, then the other bits can be deduced and are fixed.
a)
V=p+prt
now we solve for P
V=P (1+rt)
Divide both sides by (1+rt)
P=V÷(1+rt)...answer
b)
P=V÷(1+rt)
P=3,000÷(1+0.06×5)
P=2,307.69
Answer:
C. 70°
Step-by-step explanation:
The inscribed angle marked 15° intercepts an arc that is double that measure, so the intercepted arc on the right is 2×15° = 30°.
The external angle marked 20° is half the difference of the intercepted arcs, so is ...
20° = (1/2)(x - 30°)
40° = x - 30° . . . . . . multiply by 2
70° = x . . . . . . . . . . . add 30°
The value of x is 70°.
Answer:
AB=29; BC=27
Step-by-step explanation:
So they told us AB=4x+9 and that BC=5x+2, and AC=56 , now to help with the question you can draw this information on a number line. Now on a number you can see that basically AC=AB+BC.
So you would write it as such,,
4x+9+5x+2=56
Combine like terms
9x+11=56
Now you have to isolate the x by itself but first get rid of the 11.
9x+11-11=56-11
You would get
9x=45
Here you can divide 9 by both sides to isolate x.
9x/9=45/9
{x=5}
Now to find the value for both substitue x in the equations for both
1. AB=4x+9 where x is 5
4(5)+9 =AB
20+9 =AB
29=AB
You would do the same with BC
2. BC= 5x+2 where x is 5
5(5)+2= BC
25+2= BC
27=BC
If you want to check your answers you can just substitute x for 5 in the first equation we did where AC=AB+BC
