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pentagon [3]
2 years ago
8

At 6 a.m. the temperature was -6 degrees by noon the temperature has risen to 12 degrees how many degrees had the temperature ri

sen
please answer ASAP
Mathematics
2 answers:
Jet001 [13]2 years ago
6 0

Answer:

18 degrees.

Step-by-step explanation:

12 - (-6)

= 12 + 6

= 18.

IgorC [24]2 years ago
5 0

Answer: 18 degrees

Step-by-step explanation:

The easiest way to solve this problem is to first get the temperature to 0 and then add the current temperature. 0-(-6) = 6. 6+12 = 18.

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C

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EastWind [94]

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add the equations together

Step-by-step explanation:

4 ways of solving one-step equations: Adding, Substracting, multiplication and division.

5 0
3 years ago
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(e) 3x2 + 10x + 3 by x + 3<br>​
kap26 [50]

Answer:

(3x+1)(x+3) is the factorised form for the expression.

Step-by-step explanation:

:3

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We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like  

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After trying out a few numbers we get:

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and  

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⋅

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9

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1

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3

x

2

+

10

x

+

3

=

3

x

2

+

9

x

+

1

x

+

3

=

3

x

(

x

+

3

)

+

1

(

x

+

3

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(

3

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is the factorised form for the expression.

is the factorised form for the expression.

8 0
3 years ago
8c + c = what please help me i am doing test and need answer right now. like 4rl
lianna [129]

Answer: 8c

Step-by-step explanation:

We do not know the value of c or the other c.

So, the answer to the question is 8c. Hope it helped.

8 0
3 years ago
Read 2 more answers
What is the area of the figure shown?
musickatia [10]

Check the picture below.

now, we're making an assumption that, the two blue shaded region are equal in shape, and thus if that's so, that area above the 14 is 6 and below it is also 6, 14 + 6 + 6 = 26.

so hmm if we simply get the area of the trapezoid and subtract the area of the yellow triangle and the area of the cyan triangle, what's leftover is what we didn't subtract, namely the shaded region.

\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h~~=height\\ a,b=\stackrel{parallel~sides}{bases~\hfill }\\[-0.5em] \hrulefill\\ h=15\\ a=14\\ b=26 \end{cases}\implies A=\cfrac{15(14+26)}{2}\implies A=300 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Areas}}{\stackrel{trapezoid}{300}~~ - ~~\stackrel{yellow~triangle}{\cfrac{1}{2}(26)(9)}~~ - ~~\stackrel{cyan~triangle}{\cfrac{1}{2}(15)(6)}} \\\\\\ 300~~ - ~~117~~ - ~~45\implies 138\qquad \textit{blue shaded area}

8 0
2 years ago
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