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2 years ago

Can someone help me find the slope?

Mathematics

1 answer:

kipiarov [429]2 years ago

7 0

Answer:

Undefined

Step-by-step explanation:

First, take 2 points from the table given, then you use the equation y2-y1/x2-x1 to find your slope. So, if I take the coordinates (7,1) and (7,2) and plug them into my equation, I would get 2-1/7-7. If you solve this equation, you will end up wil 1/0. Now, if you have something like this as your answer, you can not find your slope. There can not be a slope because the zero is at the bottom, making this "Undefined".

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Measure to the correct location on the imaige not all angle measures will be used

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2 years ago

Read 2 more answers

In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i

PilotLPTM [1.2K]

Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,

was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

$\bf \displaystyle \int -32\cdot dt\implies -32t+C
\\\\\\
\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
\\\\\\
-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}
\\\\\\
\textit{now to get the positional s(t)}
\\\\\\
\displaystyle \int -32t\cdot dt\implies -16t^2+C
\\\\\\
\textit{the initial \underline{position} was 400ft away at 0secs}
\\\\\\
-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}$

when will it reach the ground level? let's set s(t) = 0

$\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
\\\\\\
25=t^2\implies \boxed{5=t}$

part B) check the picture below

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2 years ago

Find a 101 of the sequence 5, 8, 11, .... A. 302 B. 311 C. 305 D. 308

Dimas [21]

Answer:

305

Step-by-step explanation:

We are adding 3 each time

5+3 = 8

8+3 = 11

The formula for an arithmetic sequence is

an = a1+d(n-1) where a1 is the first term and d is the common difference

an = 5+3(n-1)

We want the 101 term

a101 = 5 +3(101-1)

= 5+3(100)

= 5+300

= 305

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2 years ago

In triangle ABC, angle A = 2x°, angle B = (x-45)° and angle C = (x-15)°.

Lelechka [254]

$Sum\ of\ angles\ in\ triangle\ is\ equal\ to\ 180^{\circ}\\\\
To\ find\ x\ sum\ all\ angles:\\
2x+x-45+x-15=180\\\\
4x-60=180\ \ \ |Add\ 60\\\\
4x=60+180\\\\
4x=240\ \ \ |Divided\ by\ 4\\\\
x=60^{\circ}\\\\
\angle \ A=2x=2*60=120^{\circ}\\
\angle\ B=x-45=60-45=15^{\circ}\\
\angle\ C=x-15=60-15=45^{\circ}\\\\Triangle\ is\ \textbf{obtuse}.$

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2 years ago