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Marrrta [24]
2 years ago
12

How do you do division/long division? I was never taught how, and now I am struggling with it. Please answer thoroughly, thanks

<3
Mathematics
1 answer:
grin007 [14]2 years ago
4 0

Answer:

See attached picture for example, hope it helps!

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Using calculus, you can find a function’s maximum or minimum by differentiating and setting the result to zero. Do this for equa
Elenna [48]

Answer:

\dfrac{dx}{d\theta}=\dfrac{2v_0^2\cos2\theta}{g}

x=\dfrac{v_0^2}{g} at \theta=45

Step-by-step explanation:

x=\dfrac{v_0^2\sin2\theta}{g}

Differentiating with respect to \theta means v_0 and g are constants. So we differentiate only the \sin2\theta term.

Assume y=\sin2\theta.

Let u=2\theta.

\dfrac{du}{d\theta}=2

Also, y becomes

y=\sin u

\dfrac{dy}{du}=\cos u

By chain rule,

\dfrac{dy}{d\theta}=\dfrac{dy}{du}\cdot \dfrac{du}{d\theta}

\dfrac{dy}{d\theta}=\cos u\cdot2=2\cos u=2\cos 2\theta

Adding back the constants,

\dfrac{dx}{d\theta} = \dfrac{2v_0^2\cos2\theta}{g}

Equating this to 0,

\dfrac{dx}{d\theta}=\dfrac{2v_0^2\cos2\theta}{g}=0

\cos2\theta=0

2\theta = \cos^{-1}0=90

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Using this value of \theta in the expression for x,

x=\dfrac{v_0^2\sin(2\times145)}{g}=\dfrac{v_0^2\sin90}{g}=\dfrac{v_0^2}{g} (since \sin90=1)

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4 years ago
Find the 12th term of the geometric sequence -2,4,-8..
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Answer:

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Step-by-step explanation:

Pattern rule : Start at -2 and multiply it by -2.

-2 x -2 = 4

4 x -2 = -8

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- 32 x -2 = 64...so on

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3 years ago
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Two times the quantity of the difference m and n is equation to x more than 7

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So 4x-6y 2(x X3y)you would have to subtract 4x with 2x
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