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2 years ago

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How do you do division/long division? I was never taught how, and now I am struggling with it. Please answer thoroughly, thanks

<3

1 answer:

grin007 [14]2 years ago

4 0

Answer:

See attached picture for example, hope it helps!

Step-by-step explanation:

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I need helpss for the problem

wel

Answer: C

Step-by-step explanation:

7 0

3 years ago

Using calculus, you can find a function’s maximum or minimum by differentiating and setting the result to zero. Do this for equa

Elenna [48]

Answer:

$\dfrac{dx}{d\theta}=\dfrac{2v_0^2\cos2\theta}{g}$

$x=\dfrac{v_0^2}{g}$ at $\theta=45$

Step-by-step explanation:

$x=\dfrac{v_0^2\sin2\theta}{g}$

Differentiating with respect to $\theta$ means $v_0$ and $g$ are constants. So we differentiate only the $\sin2\theta$ term.

Assume $y=\sin2\theta$ .

Let $u=2\theta$ .

$\dfrac{du}{d\theta}=2$

Also, $y$ becomes

$y=\sin u$

$\dfrac{dy}{du}=\cos u$

By chain rule,

$\dfrac{dy}{d\theta}=\dfrac{dy}{du}\cdot \dfrac{du}{d\theta}$

$\dfrac{dy}{d\theta}=\cos u\cdot2=2\cos u=2\cos 2\theta$

Adding back the constants,

$\dfrac{dx}{d\theta} = \dfrac{2v_0^2\cos2\theta}{g}$

Equating this to 0,

$\dfrac{dx}{d\theta}=\dfrac{2v_0^2\cos2\theta}{g}=0$

$\cos2\theta=0$

$2\theta = \cos^{-1}0=90$

$\theta=45$

Using this value of $\theta$ in the expression for $x$ ,

$x=\dfrac{v_0^2\sin(2\times145)}{g}=\dfrac{v_0^2\sin90}{g}=\dfrac{v_0^2}{g}$ (since $\sin90=1$ )

7 0

4 years ago

Find the 12th term of the geometric sequence -2,4,-8..

WINSTONCH [101]

Answer:

-16394

Step-by-step explanation:

Pattern rule : Start at -2 and multiply it by -2.

-2 x -2 = 4

4 x -2 = -8

-8 x -2 = 16

16 x -2 = -32

- 32 x -2 = 64...so on

3 0

3 years ago

Translate the equation into a sentence <br>2(m - n) = x + 7

Lelu [443]

Two times the quantity of the difference m and n is equation to x more than 7

5 0

3 years ago

Which is equivslnt to 4x - 6y? 2(x - 3y) or -2(-2x - 3y)

ludmilkaskok [199]

So 4x-6y 2(x X3y)you would have to subtract 4x with 2x

5 0

3 years ago