Question

3 of 3 Find the 10th term, T10, of the following sequence: 8,27,66, 131, 228,...

Answer 1

Answer:

T10 = 1403.

Step-by-step explanation:

8 27 66 131 228

Differences in terms are   19  39  65  97

                                              20  26  32     <-------- increasing by 6

                                               

We can extend this to    19   39  65  97   135      179       229       285      

                                            20  26  32  38     44       50           56         62

    347        415

           68  

So the 6th term is 228 + 135 = 363.

7th is 363 + 179 = 542

8th term = 542 + 229 = 771

9th term = 771 + 285 = 1056

10th term = 1056 + 347 = 1403.