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Damm [24]
3 years ago
9

Simply the expression 8x^2-3x+6x^2+5x-9

Mathematics
2 answers:
alisha [4.7K]3 years ago
5 0

Answer:

your answer should be 14x^2+2x−9


cestrela7 [59]3 years ago
3 0

Answer:

14x²+2x-9

Step-by-step explanation:

Given expression is 8x²-3x+6x²+5x-9.

Simplify as,

8x²+6x²-3x+5x-9

Add coefficients of x²,x

(8+6)x²+(-3+5)x-9

14x²+2x-9 which is the answer.


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Find a rectangular equation. X = 3tan t, Y = 2sec t, for in (−π /2 , π /2 )
anzhelika [568]

Answer:

Step-by-step explanation:

x= 3tan(t) \rightarrow tan(t) = \frac{x}{3} \rightarrow tan^2(t) = \frac{x^2}{9}

y= 2sec(t) \rightarrow sec(t) = \frac{y}{2} \rightarrow sec^2(t) = \frac{y^2}{4}

sec^2(t) -tan^2(t) =1

\frac{y^2}{4} -\frac{x^2}{9} =1

is the rectangular equation of the parameter functions.

also, it is a hyperbola. The condition -\pi/2 < t limit x from 0 to infinitive

7 0
4 years ago
The circle below has center C, and its radius is 5 in. Given that m
yan [13]
What is the question bruh not everybody know what you talkin bout
7 0
4 years ago
What is the distance between -93 and 114 on a number line???
Alborosie

Answer:

207

Step-by-step explanation:

6 0
3 years ago
Dalgliesh the detective fancies himself a shrewd judge of human nature. In careful tests it has been discovered that he is right
Dafna11 [192]

Answer:

The probability that Jones is lying is 6/7

Step-by-step explanation:

First we will list out 2 different cases when the outcome is a lie

1.probability that Jones tells lies is = 0.6 and probability that dalgiliesh analyses it correctly is 0.8

So the probability that dagliesh correctly analyses that he is telling lies is 0.8*0.6=0.48

2.Probability that Jones tells truth is 0.4 and if dagliesh analyses it incorrectly (which has a probability of 0.2) the outcome(as analysed by dagiliesh) is a lie

So probability that dagliesh analyses Jones truth as a lie is 0.2*.0.4=0.08

Total probability of outcome being a lie is 0.48+0.08=0.56

But we need the probability of Jones actually saying a lie which is nothing but 0.48/0.56= 6/7

4 0
3 years ago
Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif
dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

<u>Step:-1</u>

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals t_{0.01} =2.82  (from tabulated value).

The mean value = 0.0365

x±t_{0.01} \frac{S}{\sqrt{n-1} }

0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }

0.0365±2.82 \frac{0.0046}{\sqrt{22} }

0.0365±2.82 \frac{0.0046}{4.690 }

using calculator

0.0365±0.00276

Confidence interval is

(0.0365-0.00276,0.0365+0.00276)

(0.0338,0.0392)

the mean value is lies between in this confidence interval

(0.0338,0.0392).

<u>Answer:-</u>

<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>

4 0
3 years ago
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