On a test that has a normal distribution, a score of 49 falls two standard deviations below the mean, and a score of 61 falls on
1 answer:
The mean of this test will be 57.
<h3>What is Standard Deviation and Mean?</h3>
A standard deviation (or σ) is a measure of how dispersed the data is in relation to the mean.
The mean can be used to get an overall idea, or picture, of the data set.
Let Mean be 'm'
and standard deviation=
So, m-2=49
and, m + =61
Solving the above two equation we get
Now, m= 61-
= 61-4
= 57
So , the mean of this test will be =57
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1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,
6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*
=
(
)
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,
6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*