Y=3x+2 is the equation of a straight line graph. Where does it cross the y-axis?

1 answer:

8 0

The line crosses the y-axis at point (0,2). You know this because the slope intercept form is y=mx+b. y is any point on the y-axis. m is the slope of the line. x is and point on the x-axis. Finally, b is the y-intercept or where the line crosses the y-axis. As a result, your equation has a 2 for b. So, your answer would be: the line crosses the y-axis at point (0,2). 2 being where the line crosses the y-axis.

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What is 3/4 of 2/3? 8/9 6/12 or 1/2 12/6 or 2

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4 0

2 years ago

CAN SOMEONE PLEASE WRITE A EQUATION OF THIS LINE!!

serious [3.7K]

Answer (assuming it can be in slope-intercept form):

y = -x - 1

Step-by-step explanation:

When knowing the slope of a line and its y-intercept, you can write an equation to represent it in slope-intercept form, or y = mx + b format. Substitute the m and b for real values.

1) First, find the slope of the equation, or m. Pick any two points from the line and substitute their x and y values into the slope formula, $m = \frac{y_2-y_1}{x_2-x_1}$ . I chose the points (0, -1) and (-1, 0):

$m = \frac{(0)-(-1)}{(-1)-(0)} \\m = \frac{0+1}{-1-0} \\m = \frac{1}{-1} \\m = -1$

Thus, the slope is -1.

2) Now, find the y-intercept, or b. The y-intercept of a line is the point at which the line crosses the y-axis. By reading the graph, we can see that the line intersects the y-axis at the point (0,-1), therefore that must be the y-intercept.

3) Now, substitute the found values into the y = mx + b formula. Substitute -1 for m and -1 for b:

$y = -x -1$