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tensa zangetsu [6.8K]
3 years ago
11

Y=3x+2 is the equation of a straight line graph. Where does it cross the y-axis?

Mathematics
1 answer:
tamaranim1 [39]3 years ago
8 0
The line crosses the y-axis at point (0,2). You know this because the slope intercept form is y=mx+b. y is any point on the y-axis. m is the slope of the line. x is and point on the x-axis. Finally, b is the y-intercept or where the line crosses the y-axis. As a result, your equation has a 2 for b. So, your answer would be: the line crosses the y-axis at point (0,2). 2 being where the line crosses the y-axis.
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 3x+2(4+6x)=133

  3x+8+12x=133                      First I distibuted the 2 too the 4 and 6x

15x+8=133                                 Then I added the x es 3x and 12x

15x+8-8=133-8                         Then I subracted 8 from both sides

15x=125                                    That leaves with this

 15x/15=125/15                          Now I divide 15 from both sides to isolate x

x= 8.33333                                 that is the answer

                             check

                  3x+2(4+6x)=133

                 3*8.333333+2(4+6*8.333333)=133

                  24.999999 +2(4+ 49.999998)=133

                    24.999999+2( 53.999998)=133

                         24.999999+107.999996=133

                              132.999995=133

                       

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