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tensa zangetsu [6.8K]
3 years ago
11

Y=3x+2 is the equation of a straight line graph. Where does it cross the y-axis?

Mathematics
1 answer:
tamaranim1 [39]3 years ago
8 0
The line crosses the y-axis at point (0,2). You know this because the slope intercept form is y=mx+b. y is any point on the y-axis. m is the slope of the line. x is and point on the x-axis. Finally, b is the y-intercept or where the line crosses the y-axis. As a result, your equation has a 2 for b. So, your answer would be: the line crosses the y-axis at point (0,2). 2 being where the line crosses the y-axis.
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Can you please answer this question
tamaranim1 [39]
3tan^{2} \theta +7sec\theta=3
First I converted the equation terms into sine and cosine.
tan^{2}\theta = \frac{sin^{2}\theta}{cos^{2}\theta} and sec\theta= \frac{1}{cos\theta}
Substitution:
\frac{3sin^2\theta}{cos^2\theta} + \frac{7}{cos\theta} =3
Common Denominator Created:
\frac{3sin^2\theta}{cos^2\theta} + \frac{7cos\theta}{cos^2\theta} =3
Multiply each term by the LCD:
3sin^2\theta+7cos\theta=3cos^2\theta
Substitution: Recall ⇒sin^2\theta =1-cos^2\theta 
3(1-cos^2\theta)+7cos\theta=3cos^2\theta
Distribute and collect all terms on one side:
6cos^2\theta-7cos\theta-3=0
Factor and set each factor equal to 0:
(2cos\theta-3)(3cos\theta+1)=0
2cos\theta-3=0⇒theta=cos^{-1} \frac{3}{2}
3cos\theta+1=0⇒theta=cos^{-1} \frac{-1}{3}
The 2nd factor provides only possible answer 109.5 degrees

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3 years ago
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MrRa [10]
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Solve x^2 = 144.<br><br>A. 72 <br>B. 12<br>C. +12<br>D. -12​
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Igoryamba

Answer:

ROTATION

Step-by-step explanation:

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