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3 years ago

you did 150 J of work lifting a 120 N backpack. how much did the backpack weigh in pounds?(hint:there are 4.448 N in one pound)

1 answer:

3 0

If the backpack weighs 120 N, then the equivalent
weight in pounds is about 26.98 .

All that business about lifting and joules of work is
completely irrelevant to this question.

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write and solve a proportion to complete the statement round to the nearest hundredth if necessary . 6 km equals x mi

Anarel [89]

I don't know if this is the true answer, but I would say 3.73

7 0

3 years ago

The staff dietician at the California Institute of Trigonometry has to make up a meal with 600 calories, 20 grams of protein, an

Arlecino [84]

Answer:

The amount of rubbery jello=5.038 ounce

Dried fish stick = 4.886 ounce

Mystery meat = 1.526 ounce.

Step-by-step explanation:

Solutions/Explanation: (a) Suppose the amount of rubbery jello = $x$ ounce,

The dried fish sticks amount to be = $y$ ounce

The amount of mystery meat = ounce.

Specification of the ingredients

Rubbery jello has: Calories=10 Cal/ounce, Protien=1 gram/ounce, Vitamin C= 30 mg/ounce

Dried fish sticks: Calories=50 Cal/ounce, Protien=3 grams/ounce, Vitamin C=10 mg/ounce

Mystery meat: Calories=200 Cal/ounce, Protien=0.2 gram/ounce, Vitamin C=0 mg/ounce,

Now,

Total calories = $600$ .

Thus,

$10x+50y+200z=600\quad\Idot (1)$

The, total Protien = $20 g$ .

Thus,

$x+3y+0.2z=20 \quad\Idot (2)$

also, total Vitamin C = .

Thus,

$30x+10y+0z=200 \quad\Idot (3)$

Therefore,

1, 2 and 3 are the mathematical models of the dietician's problem with a system of three linear equations.

(b) Now, we know three equations:

$10x+50y+200z=600$

$x+5y+20=60 \quad\Idot (4)$

From eqn 2,

$x+3y+0.2z=20 \quad\Idot (5)$

From eqn 3.

$30x+10y=200$

$3x+y=20 \quad\Idot (6)$

On solving the eqn 4, 5 and 6 for $x, y$ and $z,$

Multiplying eqn 5 by 100,

$100x+300y+20z=2000 \quad\Idot (7)$

Now, subtract eqn 4 from eqn 7

$99x+295y=1940 \quad\Idot (8)$

Now, multiplying eqn 6 by 295. we have,

$885x+295y=5900 \quad\Idot (9)$

Now, subtract, eqn 8 from eqn 9, we get,

$786x=3960$

$x=\frac{3960}{786}$

$x=5.038 \quad\Idot (10)$

Now, substituting into eqn 6, we get

$y=4.886 \quad\Idot (11)$

Now, substitute eqn 10 and 11 into eqn 4, we have

$z=1.526$

4 0

3 years ago

Lily is preheating her oven before using it to bake. The initial temperature of the oven

BartSMP [9]

Answer:

10 minuets 225

20 minuets 375

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If the area of square 2 is 225 units?, and

murzikaleks [220]

Answer:

25 square units

Step-by-step explanation:

square 1 = 100 units (perimeter)

therefore each side = 25 units

square 2 = 225 square units (area)

therefore each side = 15 units

The sequence gradually decreases by 10.

Therefore square 3 each side would be 5 units.

To find the Area = 5×5

= <u>25 square units.</u>

3 0

3 years ago

For a one-sample test for a population proportion p and sample size n, why is it necessary that np0 and n(1−p0) are both at leas

tino4ka555 [31]

Using the Central Limit Theorem, it is found that these conditions are required to avoid the high variability associated with small samples.

<h3>What does the Central Limit Theorem states?</h3>

It states that for a <u>proportion p in a sample of size n</u>, the sampling distribution of sample proportion is approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1 - p)}{n}}$ , as long as $np \geq 10$ and $n(1 - p) \geq 10$ .

From the equation of the standard error, we could see that if one of the conditions is not respected, the standard error would be very high, indicating a low accuracy of the estimate, hence it is found that these conditions are required to avoid the high variability associated with small samples.

More can be learned about the Central Limit Theorem at brainly.com/question/24663213

6 0

2 years ago