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1 year ago

Pls solve question 4b. Verrry urgent . Ok tyy

Mathematics

1 answer:

kodGreya [7K]1 year ago

8 0

Answer:

$y = 3\left(x-\dfrac{3}{2}\right)^2+\dfrac{41}{4}$

Step-by-step explanation:

Given equation:

$y = 3x^2 - 9x + 17$

Factor out 3 from the first 2 terms:

$y = 3(x^2 - 3x) + 17$

Divide the coefficient of x by 2 and square it: (-3 ÷ 2)² = 9/4

Add this inside the parentheses and subtract the distributed value of it outside the parentheses:

$y = 3\left(x^2 - 3x+\dfrac{9}{4}\right) + 17-\dfrac{27}{4}$

Factor the parentheses and combine the constants:

$y = 3\left(x-\dfrac{3}{2}\right)^2+\dfrac{41}{4}$

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Given: AB || DE , AD bisects BE. Prove: ABC = DEC using the ASA postulate.

Ket [755]

Answer:

As per ASA postulate, the two triangles are congruent.

Step-by-step explanation:

We are given two triangles:

$\triangle ABC$ and $\triangle DEC$ .

AD bisects BE.

AB || DE.

Let us have a look at two properties.

1. When two lines are parallel and a line intersects both of them, then alternate angles are equal.

i.e. AB || ED and $\angle B$ and $\angle E$ are alternate angles $\Rightarrow$ $\angle B = \angle E$ .

2. When two lines are cutting each other, angles formed at the crossing of two, are known as Vertically opposite angles and they are are equal.

$\Rightarrow \angle ACB = \angle DCE$

Also, it is given that AD bisects BE.

i.e. EC = CB

1. $\angle B = \angle E$

2. EC = CB

3. $\angle ACB = \angle DCE$

So, we can in see that in $\triangle ABC$ and $\triangle DEC$ , two angles are equal and side between them is also equal to each other.

Hence, proved that $\triangle ABC$ $\cong$ $\triangle DEC$ .

8 0

3 years ago

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joja [24]

Answer:

Slope of the line x +2y =14 will be -1/2 since y = -1/2x+7, where m = -1/2 and c = 7.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Solve the system of equations. x+y=4 y=x^2 - 8x + 16 a) {(-3,7).(-4, 8)} b) [(4,0)} c) {(3,1),(4,0) d) {(3,7). (4.0)} e) none

Marysya12 [62]

Answer: The required solution of the given system is

(x, y) = (3, 1) and (4, 0).

Step-by-step explanation: We are given to solve the following system of equations :

$x+y=4~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=x^2-8x+16~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

From equation (i), we have

$x+y=4\\\\\Rightarrow y=4-x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of y from equation (iii) in equation (ii), we get

$y=x^2-8x+16\\\\\Rightarrow 4-x=x^2-8x+16\\\\\Rightarrow x^2-8x+16-4+x=0\\\\\Rightarrow x^2-7x+12=0\\\\\Rightarrow x^2-4x-3x+12=0\\\\\Rightarrow x(x-4)-3(x-4)=0\\\\\Rightarrow (x-3)(x-4)=0\\\\\Rightarrow x-3=0,~~~~~~~x-4=0\\\\\Rightarrow x=3,~4.$

When, x = 3, then from (iii), we get

$y=4-3=1.$

And, when x = 4, then from (iii), we get

$y=4-4=0.$

Thus, the required solution of the given system is

(x, y) = (3, 1) and (4, 0).

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3 years ago

Mr. Hollins determines that he gives away $800 each month. If he gives away 16% of his budget, then how much is his overall budg

Fynjy0 [20]

Answer:

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Step-by-step explanation:

Let his budget be x

16% of x is 800 dollars

.16 * x = 800

Divide each side by .16

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borishaifa [10]

(x,y)
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3 years ago