Question

Pls solve question 4b. Verrry urgent . Ok tyy

Answer 1

Answer:

$y = 3\left(x-\dfrac{3}{2}\right)^2+\dfrac{41}{4}$

Step-by-step explanation:

Given equation:

$y = 3x^2 - 9x + 17$

Factor out 3 from the first 2 terms:

$y = 3(x^2 - 3x) + 17$

Divide the coefficient of x by 2 and square it:  (-3 ÷ 2)² = 9/4

Add this inside the parentheses and subtract the distributed value of it outside the parentheses:

$y = 3\left(x^2 - 3x+\dfrac{9}{4}\right) + 17-\dfrac{27}{4}$

Factor the parentheses and combine the constants:

$y = 3\left(x-\dfrac{3}{2}\right)^2+\dfrac{41}{4}$