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2 years ago

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One of the Confederation's accomplishments was an arrangement for

1 answer:

Dovator [93]2 years ago

6 0

New states in the west

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A tee-ball team for 5 year-olds has half as many girls as boys. If there are 15 children on the team, how many are boys and how

Usimov [2.4K]

There are 10 boys because half of 10 is 5 5+5 equals 10

4 0

3 years ago

Read 2 more answers

Allen is showing his work in simplifying –8.3 + 9.2 – 4.4 + 3.7. Identify and explain any errors in his work or in his reasoning

Bas_tet [7]

Answer:

try a

Step-by-step explanation:

4 0

2 years ago

Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

<u>Applying formula (1):</u>

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

<u>Applying formula (2):</u>

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

8 0

2 years ago

One end of a line segment has the coordinates (-6,2). If

CaHeK987 [17]

Answer:

The coordinates of the other end is $(16,2)$

Step-by-step explanation:

Given

$End 1: (-6,2)$

$Midpoint: (5,2)$

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

So

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

Where $(x_1,y_1) = (-6,2)$ and $(x,y) = (5,2)$

So, we're solving for $(x_2,y_2)$

Solving for $x_2$

$x = \frac{x_1 + x_2}{2}$

Substitute 5 for x and -6 for x₁

$5 = \frac{-6 + x_2}{2}$

Multiply both sides by 2

$2 * 5 = \frac{-6 + x_2}{2} * 2$

$10 = -6 + x_2$

Add 6 to both sides

$6 + 10 = -6 +6 + x_2$

$x_2 = 16$

Solving for $y_2$

$y = \frac{y_1 + y_2}{2}$

Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

$2 * 2 = \frac{2 + y_2}{2} * 2$

$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

3 0

2 years ago

Each pack of batteries cost $21. How many i can buy if i have $63?

Rashid [163]

Each pack of batteries cost $21 each.
And then you have $63.

The operation to be used: Division.

63 ÷ 21 ==

Answer: 3

= You can buy 3 packs of batteries with your $63.

6 0

3 years ago

Read 2 more answers