3 years ago

Write a quadratic equation in standard form that has two solutions, -9 and 3

1 answer:

8 0

So for this you need the two solutions to be x= -9 and x=3 then move over the numbers and put in brackets (x+9)(x-3) then multiply together x^2+9x-3x-27 then combine like terms to get x^2+6-27

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Which is the additive inverse of the complex number -8+3i?

lawyer [7]

The additive inverse of a complex z is a complex number $-z,$ so that

$\mathsf{z+(-z)=-z+z=0+0i=0}$

Finding $-z:$

$\mathsf{z=-8+3i}\\\\\\ \mathsf{z+(-z)=0+0i}\\\\\ \mathsf{-8+3i+(-z)=0+0i}\\\\ \mathsf{-z=0+0i+8-3i}\\\\ \mathsf{-z=(0+8)+(0i-3i)}\\\\ \boxed{\begin{array}{c}\mathsf{-z=8-3i} \end{array}}\qquad\checkmark$

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Tags: <em>complex number additive inverse opposite algebra</em>

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anyanavicka [17]

I'm not 100% sure, but I'm pretty sure it's 1/12, 1/12, 1/12, 1/12

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In this equation What is 77+23

kondaur [170]

The answer is 100 I’m sure

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