A rhombus has four equal sides. If the perimeter of this rhombus is 164, then the length of one side is 164/4, or 41.
Draw this rhombus. Label all four sides with "41." Label the longer diagonal 80 and the half length of that diagonal 40. You will see inside the rhombus four congruent triangles with hypotenuse 41, leg 10 and unknown height. Thus, this unknown height is found by solving x^2 + 40^2 = 41^2, and x^2=9, so that the length of the shorter diagonal is 2(2) = 18 (answer).
Answer:
122.5 lbs
Step-by-step explanation:
The relation between force, wind speed, and area can be written ...
f = ks²a
for some wind speed s and area a.
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The constant of proportionality, k, can be found from the given data.
64.8 = k(18²)(500) . . . force in pounds, area in square feet, speed in mph
k = 64.8/(324×500) = 0.0004
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Using the equation with the second set of data, we have ...
f = 0.0004(35²)(250) = 122.5 . . . . pounds
The force on the 250 square foot sail would be 122.5 pounds.
Answer: I believe it is $23.99
Explanation:
19.99+10= 29.99
29.99x0.2= 5.992
29.99-5.99= $23.99
I hope this helped!
Answer:
50 kg water.
Step-by-step explanation:
We have been given that the number of kilograms of water in a human body varies directly as the mass of the body.
We know that two directly proportional quantities are in form 
, where y varies directly with x and k is constant of variation.
We are told that an 87-kg person contains 58 kg of water. We can represent this information in an equation as:
Let us find the constant of variation as:
The equation 
represents the relation between water (y) in a human body with respect to mass of the body (x).
To find the amount of water in a 75-kg person, we will substitute 
in our given equation and solve for y.
Therefore, there are 50 kg of water in a 75-kg person.
