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Lynna [10]
2 years ago
15

If a preferred (faster) learned route over a WAN has administrative distance 110 that competes with a static backup (slower) rou

te, what will the engineer need to set the distance to for the static link so that it becomes a floating static route
Computers and Technology
1 answer:
almond37 [142]2 years ago
5 0

The engineer will need to set the distance to 130 for the static link so that it becomes a floating static route.

<h3>What is Floating static routes?</h3>

This is known to be a static routes that is said to have a kind of administrative distance that is also known to be bigger than the administrative distance of any other static route or dynamic routes.

Note that the value 130 stands for the next most logical value, nd as such it is to know that the right route comes first in the steps for administrative distance.

Learn more about WAN from

brainly.com/question/11352260

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What is the value of the variable named result after the following code executes?
Makovka662 [10]

Answer:

The value of result is 20

Explanation:

Given

The above code segment

Required

The value of result

In the first line, we have:

X = 5; Y = 3; Z = 2

In the second, we have:

result = (X + Y)/Z * X

This implies that:

result = (5 + 3)/2 * 5

result = 8/2 * 5

result = 4 * 5

result = 20

3 0
2 years ago
Computers are said to use binary data because all computer data is simply a series of Os and 1s.
Bingel [31]

Answer:

True

Explanation:

The option that answers the question is "True" and this is due to the fact that computers and computing devices represent data using 0s and 1s .

Although, the users of the computer do not have to study binary digits before they are able to interact with the computer, the computer itself can not function without binary digits.

So, for every input you pass to the computer, a translator translates it to binary for the computer to understand your input.

Hence, the statement in the question is true.

7 0
3 years ago
What is the maximum number of communication paths for a team of twenty people?
MAVERICK [17]
Each of the 20 people has 19 other people to communicate to. If you add that all up you get 20*19 paths, but then each path is counted twice (back and forth), so we divide this by 2. 20*19/2 = 190.

The general forumula is n(n-1)/2
6 0
3 years ago
100 POINTS NEED THIS BEFORE 11:59 TODAY!!!!!!!!!!!!!!!
AVprozaik [17]

Answer:ok be how hobrhkihfehgdhdj fuiufiisefif jfkijfjfhhfhfhfhf

Explanation:

5 0
2 years ago
The major objective of this lab is to practice class and object-oriented programming (OOP), and separate files: 1. We will reuse
vovangra [49]

Answer:

Implementation of resistor.cpp

#include "resistor.h"

Ohms::Ohm()

{

// default constructor

voltage=0;

}

Ohms::Ohm( double x) // parameterised constructor

{

voltage = x; // voltage x set to the supply voltage in the private data field called voltage

}

Ohms:: setVoltage(double a)

{

voltage = a;// to set supply voltage in private data field called voltage

}

Ohms::setOneResistance( String s, double p)

{

cin>>p; //enter the resistance value

if(p<=0) // if resistance is less than or equals to 0

return false

else // if re

cin.getline(s);

}

Ohms::getVoltage()

{

return voltage; //return voltage of ckt

}

Ohms::getCurrent()

{

return current; //return current of ckt

}

Ohms:: getNode()

{

return resistors; //return resistors of ckt

}

Ohms::sumResist()

{

double tot_resist = accumulate(resistors.begin(),resistors.end(),0); //std::accumulate function for calculating sum //of vectors and following are the starting and ending points

return tot_resist;

}

Ohms::calcCurrent()

{

if(current <=0) // if current is less than or equal to 0

return false;

else   // if current is greater than 0

return true;

}

Ohms:: calcVoltageAcross()

{

if(voltage<=0) // if voltage is less than or equal to 0

return false;

else //if voltage greater than 0

return true;

}

Explanation:

in the case of main.cpp its simple just make a class object and remember to include resistors.cpp with it for which the second last picture describes the process precisely. (Hint: Use theunit test case functions in the main.cpp).

As you can see node is a structure consisting of member variables, followed by a class Ohms representing a DC circuit.

By looking at these pictures, it is needed to implement the main.cpp and resistor.cpp files. The user defined header file resistor.h already consists of all contents of Class Ohm, struct node. You don't need to modify it in anyway in such case.

8 0
3 years ago
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