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2 years ago

Which statement is true about a catalyst?

Chemistry

2 answers:

pentagon [3]2 years ago

7 0

Answer:

The answer is D. It changes the final products of the reaction. .

Explanation:

. Catalyst is a substance that increases the rate of a reaction without itself being consumed.

kvasek [131]2 years ago

4 0

Answer:

Explanation:

Catalysts help a reaction procede to the final products, but catalysts do not get used ( think of the catlytic converter in cars' exhaust systems)

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Which of the following is an indication of a physical change?

blagie [28]

I would like to say c

6 0

3 years ago

Read 2 more answers

Explain the difference between extensive properties and intensive properties.

Gnom [1K]

Answer:

Extensive properties depend on de mass, intensive properties not.

Explanation:

The extensive properties depend on the mass and change with the addition or reducction of the mass.

The intensive properties dont depend on the mass. For example: temperature.

I hope I help you.

5 0

3 years ago

An acid solution is 0.100 M in HCl and 0.210 M in H2SO4. What volume of a 0.150 M solution of KOH must be added to 500.0 mL of t

Dmitry_Shevchenko [17]

Answer:

When we add 0.33L of KOH only the HCl solution will be neutralized. When we add 1.4 L of KOH, all of the acid (the HCl and H2SO4 solution) will be neutralized.

Explanation:

Step 1: Data given

The solution has 0.100 M HCl and 0.210 M H2SO4

Molarity KOH = 0.150 M

Volume of acid solution = 500 mL = 0.5 L

Step 2: Calculate moles of HCl

Moles HCl = Molarity HCl * volume

Moles HCl = 0.100 M * 0.5 L

Moles HCl = 0.05 moles

Step 3: Calculate moles of H2SO4

Moles H2SO4 = 0.210 M * 0.5 L

Moles H2SO4 = 0.105 moles

Step 4: The balanced neutralization reaction of KOH with HCl can be written as:

KOH + HCl → KCl + H2O

The mole ratio is 1:1

This means to neutralize 0.05 moles HCl, we need 0.05 moles KOH

Step 5: The balanced neutralization reaction of KOH with H2SO4 can be written as:

2KOH + H2SO4 → K2SO4 + 2H2O

The mole ratio KOH: H2SO4 is 2:1

This means to neutralize 0.105 moles H2SO4 we need 0.210 moles KOH

Step 6: Calculate volume of KOH needed to neutralize the solution

To neutralize the HCl solution: 0.05 moles / 0.150 M = 0.33 L KOH needed

To neutralize the H2SO4 solution: 0.210 moles / 0.150 M = 1.4 L KOH needed

When we add 0.33L of KOH the HCl solution will be neutralized. When we add 1.4 L of KOH the HCl and H2SO4 solution will be neutralized.

4 0

3 years ago

As the temperature in a sample of gas molecules increases, which of the other properties of the gas molecules could be caused to

Ilia_Sergeevich [38]

Increase: volume, pressure, kinetic energy, gas particle collisions

Stays the same: number of moles of gas

3 0

3 years ago

1CuCl2 + 2Na(NO3) --> 1Cu(NO3)2 + 2NaCl

vivado [14]

Answer:

13.45 grams of NaCl will be produced

Explanation:

Given:

Mass of CuCl2 = 15 grams

Molar mass of CuCl2 = 134.5 g/mol

Mass of Na(NO3) = 20grams

Molar mass of Na(NO3) = 85 g/mol

To find:

Amount of Sodium chloride produced = ?

Solution:

No of moles of CuCl2 = 15/134.5 = 0.11 moles

No of moles of Na(NO3) = 20/85 = 0.23 moles,

1CuCl2 + 2Na(NO3) --> 1Cu(NO3)2 + 2NaCl

from the reaction, 1 mole of copper chloride reacts with 2 mole of NaNO3 to produce 2 moles of sodium chloride.

Hence, 0.11 mole of copper chloride will react with 0.23 mole of NaNO3 to produce 0.23 moles of sodium chloride.

Mass of 0.23 moles of NaCl = 0.23 × M.M of NaCl

(Molar mass of NaCl = 58.5)

Mass of 0.23 moles of NaCl = 0.23 × 58.5 = 13.45 grams

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3 0

3 years ago