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2 years ago

Which statement is true about a catalyst?

Chemistry

2 answers:

pentagon [3]2 years ago

7 0

Answer:

The answer is D. It changes the final products of the reaction. .

Explanation:

. Catalyst is a substance that increases the rate of a reaction without itself being consumed.

kvasek [131]2 years ago

4 0

Answer:

Explanation:

Catalysts help a reaction procede to the final products, but catalysts do not get used ( think of the catlytic converter in cars' exhaust systems)

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The group of molecules called nucleotides contain:

Grace [21]

The group of molecules called nucleotides contain phosphate groups, pyrimidines, purines, and pentose (a 5-carbon sugar). Therefore, E. all of the above is the correct answer.

8 0

3 years ago

______and __________ factors can affect an organism’s genetic traits

Flura [38]

Answer:

i think its Environmental and mutagens

Explanation:

7 0

3 years ago

What is the difference between fluorine and oxygen?

mojhsa [17]

Answer:

Continuing on across the periodic table we see that fluorine is the next element after oxygen. ... Rather than forming seven bonds fluorine only forms a single bond for basically the same reasons that oxygen only forms two bonds. Hydrogen fluoride, HF, has one bond, but four centers of electron density around the fluorine.

3 0

3 years ago

Which of the following metal atoms only form one type of positive change ? K Cu Fe Mg

IRINA_888 [86]

I believe that the correct answer is K.

7 0

3 years ago

How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? How many mL o

Rama09 [41]

Answer:

We need 75 mL of 0.1 M NaOH ( Option C)

Explanation:

Step 1: Data given

Molarity of NaOH solution = 0.100 M

volume of 0.150 M CH3COOH = 50.00 mL = 0.05 L

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles of CH3COOH

Moles CH3COOH = Molarity * volume

Moles CH3COOH = 0.150 M * 0.05 L

Moles CH3COOH = 0.0075 moles

Step 4: Calculate moles of NaOH

For 1 mol of CH3COOH we need 1 mol of NaOH

For 0.0075 mol CH3COOH we need 0.0075 mole of NaOH

Step 5: Calculate volume of NaOH

volume = moles / molarity

volume = 0.0075 moles / 0.100 M

Volume = 0.075 L = 75 mL

We need 75 mL of 0.1 M NaOH

7 0

3 years ago